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NEET General Principles and Processes of Isolation of Elements Previous Year Questions with Solutions

Complete repository of official NTA NEET questions for General Principles and Processes of Isolation of Elements from 2020 to 2026. Every question includes 30-second elimination tricks, step-by-step NCERT solutions, option-by-option traps, and official answer keys.

4 Questions 3 Exam Years (2023, 2021, 2020) 2 Easy · 2 Medium · 0 Challenging
NEET 2023 · Q97 Medium
Official NEET 2023 Question 97 - General Principles and Processes of Isolation of Elements
1
2 ✓ Key
3
4
💡 Verified Solution & 30-Second Hack
✓
Verified Against NTA Final Answer Key
Option (2) : Fe₂O₃ + CO → 2FeO + CO₂
📚 General Principles and Processes of Isolation of Elements Medium
📋 Given Parameters & Problem Setup
Process Extraction of iron in blast furnace
Specified temperature range 900 K to 1500 K (higher temperature zone)
Question requirement Reaction that does NOT take place in this range
⚡

The 30-Second Exam Hall Shortcut: ⚡ Blast Furnace Thermal Zone Division: Reduction of Fe₂O₃ Occurs at Top (500–800 K)!

⏱️ Save ~30 seconds

In a blast furnace, reduction of haematite (Fe₂O₃) by CO occurs at the TOP in the LOWER temperature zone (500 K – 800 K): Fe₂O₃ + CO ⟶ 2 FeO + CO₂. The higher temperature zone (900 K – 1500 K) in the middle/lower part features C + CO₂ ⟶ 2 CO, FeO + CO ⟶ Fe + CO₂, and slag formation CaO + SiO₂ ⟶ CaSiO₃! Therefore, reaction (2) does NOT occur in 900–1500 K! Lock Option (2) in 10 seconds!

1 Check Lower Temperature Range (500 K – 800 K, top of furnace):
2 - 3 Fe₂O₃ + CO ⟶ 2 Fe₃O₄ + CO₂
3 - Fe₃O₄ + 4 CO ⟶ 3 Fe + 4 CO₂
4 - Fe₂O₃ + CO ⟶ 2 FeO + CO₂
5 Check Higher Temperature Range (900 K – 1500 K, middle/lower furnace):
6 - C + CO₂ ⟶ 2 CO
7 - FeO + CO ⟶ Fe + CO₂
8 - CaCO₃ ⟶ CaO + CO₂
9 - CaO + SiO₂ ⟶ CaSiO₃ (slag formation)
10 Reaction (2) belongs exclusively to 500–800 K, so it does NOT take place in 900–1500 K.
11 Match Option (2) directly.
🛡️
Why You Can 100% Trust This Shortcut: Verbatim NCERT Metallurgy Figure 6.6 & Blast Furnace thermal zone descriptions.
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Thermal Profile of the Blast Furnace

The blast furnace is divided into thermal zones based on height: (a) Upper lower-temperature zone (500 K to 800 K), and (b) Middle-to-lower higher-temperature zone (900 K to 1500 K):

Zones: 500 K−800 K⏟Upper (Reduction of Fe2O3)⟷900 K−1500 K⏟Middle/Lower (Reduction of FeO, Slag, CO gen)\text{Zones: } \underbrace{500\text{ K} - 800\text{ K}}_{\text{Upper (Reduction of } \text{Fe}_2\text{O}_3)} \quad \longleftrightarrow \quad \underbrace{900\text{ K} - 1500\text{ K}}_{\text{Middle/Lower (Reduction of FeO, Slag, CO gen)}}
Step 2

Reactions in the Lower Temperature Range (500 K – 800 K)

At the top of the furnace, haematite (Fe₂O₃) is reduced in stages by carbon monoxide at 500 K – 800 K:

3Fe2O3+CO⟶2Fe3O4+CO2Fe3O4+4CO⟶3Fe+4CO2Fe2O3+CO⟶2FeO+CO2(Occurs at 500 K−800 K)\begin{aligned} 3\text{Fe}_2\text{O}_3 + \text{CO} &\longrightarrow 2\text{Fe}_3\text{O}_4 + \text{CO}_2 \\ \text{Fe}_3\text{O}_4 + 4\text{CO} &\longrightarrow 3\text{Fe} + 4\text{CO}_2 \\ \text{Fe}_2\text{O}_3 + \text{CO} &\longrightarrow 2\text{FeO} + \text{CO}_2 \quad (\text{Occurs at } 500\text{ K} - 800\text{ K}) \end{aligned}
Step 3

Reactions in the Higher Temperature Range (900 K – 1500 K)

In the 900 K to 1500 K zone, carbon dioxide is reduced by coke, FeO is reduced to iron, and limestone forms slag:

C+CO2⟶2COFeO+CO⟶Fe+CO2CaCO3⟶CaO+CO2CaO+SiO2⟶CaSiO3(Slag formation)\begin{aligned} \text{C} + \text{CO}_2 &\longrightarrow 2\text{CO} \\ \text{FeO} + \text{CO} &\longrightarrow \text{Fe} + \text{CO}_2 \\ \text{CaCO}_3 &\longrightarrow \text{CaO} + \text{CO}_2 \\ \text{CaO} + \text{SiO}_2 &\longrightarrow \text{CaSiO}_3 \quad (\text{Slag formation}) \end{aligned}
Step 4

Identify the Reaction that Does NOT Take Place in 900–1500 K

Reaction (2), Fe₂O₃ + CO ⟶ 2 FeO + CO₂, takes place strictly at the lower temperatures (500 K – 800 K). Therefore, it does NOT occur in the 900 K to 1500 K range:

Fe2O3+CO⟶2FeO+CO2(Does NOT occur at 900 K−1500 K)\text{Fe}_2\text{O}_3 + \text{CO} \longrightarrow 2\text{FeO} + \text{CO}_2 \quad (\text{Does NOT occur at } 900\text{ K} - 1500\text{ K})
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 (1)
✗ Incorrect
Verdict & Scientific Reason:

Slag formation occurs actively between 1070 K and 1270 K (inside 900 K – 1500 K).

⚠️
Student Fallacy (Why candidates pick this trap): Candidate forgot the temperature of slag formation in the middle zone.
2 (2)
✓ 100% Correct
Verdict & Scientific Reason:

Accurate: This reduction step occurs at the cooler top of the blast furnace (500 K – 800 K), not between 900 K and 1500 K.

💡
Why this is airtight: None. Candidate correctly correlated reaction thermodynamics with furnace temperature zones.
3 (3)
✗ Incorrect
Verdict & Scientific Reason:

Reduction of FeO to Fe takes place directly within the 900 K – 1500 K range.

⚠️
Student Fallacy (Why candidates pick this trap): Candidate confused the reduction of FeO with the reduction of Fe₂O₃.
4 (4)
✗ Incorrect
Verdict & Scientific Reason:

The endothermic Boudouard reaction occurs at high temperatures (around 1000 K – 1200 K).

⚠️
Student Fallacy (Why candidates pick this trap): Candidate did not recognize that coke reduction of CO₂ requires high temperature.
⚠️

NTA Trap Alert: Confusing Low and High Temperature Reduction Steps

Students remember that CO reduces iron oxides throughout the furnace, but forget that Fe₂O₃ is reduced to FeO at the top (cooler zone, 500–800 K), and FeO is reduced to molten Fe in the hotter zone (900–1500 K).

🛡️ How to avoid the -1 mark: Remember: Fe₂O₃ reduction = Top (cooler, 500–800 K); FeO reduction + Slag formation = Middle/Bottom (hotter, 900–1500 K).
📖

Core NEET Syllabus Standard

National Eligibility cum Entrance Test (NEET UG) · General Principles and Processes of Isolation of Elements Standard Benchmark
Core Scientific Principle Tested:

"Reduction of Fe₂O₃ by CO proceeds in the upper low-temperature zone (500–800 K); reduction of FeO and slag formation occur at 900–1500 K."

Syllabus Focus: Extraction of Iron from its Oxides – Blast Furnace
Preserved in Rationalized Curriculum Syllabus & Academic Standards ↗
NEET 2021 · Q65 Easy
Official NEET 2021 Question 65 - General Principles and Processes of Isolation of Elements
1 Electrolysis
2 Chromatography
3 Distillation ✓ Key
4 Zone refining
💡 Verified Solution & 30-Second Hack
✓
Verified Against NTA Final Answer Key
Option (3) : Distillation
📚 General Principles and Processes of Isolation of Elements Easy
📋 Given Parameters & Problem Setup
Condition Highly pure metal which is liquid at room temperature (Mercury, Hg)
⚡

The 30-Second Exam Hall Shortcut: ⚡ Liquid Metal = Mercury (Low Boiling Point)   ⟹  \implies Distillation!

⏱️ Save ~20 seconds

The only metal that is liquid at room temperature is Mercury (HgHg). Mercury has an extraordinarily low boiling point (356.7∘C356.7^\circ\text{C}). The standard NCERT refining method for low-boiling metals (Zinc and Mercury) is DISTILLATION! Match Option (3)!

1 Identify the metal: "metal which is liquid at room temperature"   ⟹  \implies Mercury (HgHg).
2 Recall NCERT Refining of Metals section: "Distillation: This is very useful for low boiling metals like zinc and mercury. The impure metal is evaporated to obtain the pure metal as distillate."
3 Other methods: Zone refining is used for semiconductors (Si, Ge); Electrolysis is used for Cu, Al; Chromatography is used when impurities have similar chemical properties.
4 Match Option (3) Distillation.
🛡️
Why You Can 100% Trust This Shortcut: Canonical NCERT Metallurgy section on Refining (Distillation).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Identifying the Target Metal

Mercury (HgHg, atomic number 80) is the only metallic element that exists in the liquid state at standard room temperature (25∘C25^\circ\text{C} / 298 K298\text{ K}), having a melting point of −38.83∘C-38.83^\circ\text{C}.

Step 2

Evaluating Refining Techniques Described in NCERT

NCERT categorizes metal refining processes based on physical properties: - Distillation: Used specifically for metals with low boiling points, such as Zinc (ZnZn) and Mercury (HgHg). The impure volatile metal is vaporized and condensed as pure distillate, leaving non-volatile impurities behind. - Electrolysis: Applied to reactive or common industrial metals like copper, aluminum, and gold. - Zone Refining: Applied to ultra-pure semiconductors (Germanium, Silicon, Boron, Gallium, Indium). - Chromatography: Utilized when elements to be separated are available in minute quantities and exhibit close chemical similarities.

Step 3

Conclusion

Distillation is the designated metallurgical method to obtain highly pure mercury, corresponding to Option (3).

⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 1
✗ Incorrect
Verdict & Scientific Reason:

Standard refining method for copper, silver, and aluminum, but not the specific industrial method for liquid mercury.

⚠️
Student Fallacy (Why candidates pick this trap): Assuming electrolysis is universal for all metals.
2 2
✗ Incorrect
Verdict & Scientific Reason:

Employed for microgram separations and lanthanoids/actinoids, not bulk mercury purification.

⚠️
Student Fallacy (Why candidates pick this trap): Overcomplicating the separation technique.
3 3
✓ 100% Correct
Verdict & Scientific Reason:

Verbatim NCERT refining method for low-boiling volatile metals like zinc and liquid mercury.

💡
Why this is airtight: None; textbook metallurgy precision.
4 4
✗ Incorrect
Verdict & Scientific Reason:

Used for solid semiconductor metals (Ge,Si,GaGe, Si, Ga) based on fractional crystallization.

⚠️
Student Fallacy (Why candidates pick this trap): Confusing semiconductor purification with low-boiling metal refining.
⚠️

NTA Trap Alert: Zone Refining vs. Distillation Trap

Students who see "highly pure metal" often instinctively guess Zone Refining (Option 4) because zone refining produces high-purity semiconductors. However, zone refining relies on a moving molten zone in a SOLID ingot, making it impossible for a metal that is already liquid at room temperature (Mercury).

🛡️ How to avoid the -1 mark: Liquid metal at room temperature   ⟹  Hg  ⟹  \implies Hg \implies volatile   ⟹  \implies Distillation.
📖

Core NEET Syllabus Standard

NCERT Chemistry · General Principles and Processes of Isolation of Elements Standard Benchmark
Core Scientific Principle Tested:

"Distillation is used to refine low-boiling metals such as zinc and mercury by converting the metal into vapor while impurities remain behind."

Syllabus Focus: Refining of Metals (Distillation)
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗
NEET 2021 · Q69 Easy
Official NEET 2021 Question 69 - General Principles and Processes of Isolation of Elements
1 upto 1200 K
2 upto 2200 K ✓ Key
3 upto 1900 K
4 upto 5000 K
💡 Verified Solution & 30-Second Hack
✓
Verified Against NTA Final Answer Key
Option (2) : upto 2200 K
📚 General Principles and Processes of Isolation of Elements Easy
📋 Given Parameters & Problem Setup
Industrial Apparatus Blast furnace for iron extraction
Target Maximum temperature achieved in the furnace
⚡

The 30-Second Exam Hall Shortcut: ⚡ Combustion Zone Tuyeres: ~2200 K

⏱️ Save ~15 seconds

Near the base of the blast furnace where preheated air blasts through tuyeres, exothermic combustion of coke (C+O2→CO2C + O_2 \to CO_2) elevates temperature to its maximum of ≈2200 K\approx 2200\text{ K}. As hot gases ascend, temperature cools from 2200 K2200\text{ K} at the bottom to ≈500−800 K\approx 500-800\text{ K} at the top! Match Option (2)!

1 Blast furnace temperature profile ranges from ≈500 K\approx 500\text{ K} at the top to ≈2200 K\approx 2200\text{ K} at the bottom.
2 At the combustion zone near tuyeres: C+O2→CO2C + O_2 \to CO_2 (strongly exothermic, ΔH=−393.5 kJ/mol\Delta H = -393.5\text{ kJ/mol}).
3 Maximum temperature reached in this lower combustion zone is upto 2200 K2200\text{ K}.
4 Match Option (2).
🛡️
Why You Can 100% Trust This Shortcut: Canonical NCERT Metallurgy section and blast furnace diagram schematic.
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Thermal Zonation in a Blast Furnace

In the industrial metallurgy of iron (extraction from haematite Fe2O3Fe_2O_3), the blast furnace exhibits a continuous vertical temperature gradient: - Top Zone (Reduction Zone): 500 K−800 K500\text{ K} - 800\text{ K} - Middle Zone (Slag Formation & Reduction of FeO): 900 K−1500 K900\text{ K} - 1500\text{ K} - Lower Zone (Combustion & Fusion Zone): 1500 K−2200 K1500\text{ K} - 2200\text{ K}

Step 2

Combustion Zone Chemical Reactions

At the bottom of the blast furnace, oxygen in the blast of hot air burns descending coke to generate carbon dioxide and immense thermal energy:

C(s)+O2(g)⟶CO2(g),ΔHcirc=−393.5 kJ/molC(s) + O_2(g) \longrightarrow CO_2(g), \quad \Delta H^circ = -393.5\text{ kJ/mol}
Step 3

Maximum Attainable Temperature

According to NCERT Metallurgy, the intense heat released in this localized exothermic reaction drives the temperature up to about 2200 K in the combustion zone.

Tmax≈2200 KT_{\text{max}} \approx 2200\text{ K}
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 1
✗ Incorrect
Verdict & Scientific Reason:

This is the intermediate temperature in the middle zone (reduction of FeO and limestone decomposition), not the maximum.

⚠️
Student Fallacy (Why candidates pick this trap): Confusing middle reduction zone temperature with combustion zone.
2 2
✓ 100% Correct
Verdict & Scientific Reason:

Verbatim NCERT specification for the maximum temperature attained in the blast furnace combustion zone.

💡
Why this is airtight: None; precise textbook recall.
3 3
✗ Incorrect
Verdict & Scientific Reason:

Close but below the peak combustion temperature of 2200 K.

⚠️
Student Fallacy (Why candidates pick this trap): Underestimating peak combustion temperature.
4 4
✗ Incorrect
Verdict & Scientific Reason:

Unrealistically high; such extreme temperatures would melt the refractory brick lining.

⚠️
Student Fallacy (Why candidates pick this trap): Overestimating furnace operational limits.
⚠️

NTA Trap Alert: Reduction Temperature vs. Maximum Combustion Temperature Trap

Students frequently remember temperatures like 1073 K1073\text{ K} (where the Ellingham curves intersect) or 1200 K1200\text{ K} (reduction of FeO by C), and confuse them with the MAXIMUM temperature in the furnace, which reaches 2200 K2200\text{ K} at the tuyere level.

🛡️ How to avoid the -1 mark: Max temperature in blast furnace = 2200 K2200\text{ K} (bottom combustion zone).
📖

Core NEET Syllabus Standard

NCERT Chemistry · General Principles and Processes of Isolation of Elements Standard Benchmark
Core Scientific Principle Tested:

"In the lower combustion zone of the blast furnace, burning of coke produces temperatures up to about 2200 K."

Syllabus Focus: Extraction of Iron from its Oxides (Blast Furnace)
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗
NEET 2020 · Q111 Medium
Official NEET 2020 Question 111 - General Principles and Processes of Isolation of Elements
1 Wrought iron is impure iron with 4% carbon.
2 Blister copper has blistered appearance due to evolution of CO2.
3 Vapour phase refining is carried out for Nickel by Van Arkel method.
4 Pig iron can be moulded into a variety of shapes. ✓ Key
💡 Verified Solution & 30-Second Hack
✓
Verified Against NTA Final Answer Key
Option (4) : Pig iron can be moulded into a variety of shapes.
📚 General Principles and Processes of Isolation of Elements Medium
📋 Given Parameters & Problem Setup
Topic General Principles and Processes of Isolation of Elements (Metallurgy)
Question Objective Identify the CORRECT statement from the given choices
⚡

The 30-Second Exam Hall Shortcut: ⚡ "Eliminate False Statements: Wrought iron is purest (<0.2% C); Blister copper is due to SO2; Ni refined by Mond process!"

⏱️ 25 seconds

Statement (1) is false because Wrought iron is the PUREST commercial iron (<0.2% C), not 4% C (Pig iron has 4% C). Statement (2) is false because blister copper gets blisters due to evolution of SO2SO_2, NOT CO2CO_2. Statement (3) is false because Nickel is refined by MOND process (Van Arkel is for Zr and Ti). By elimination, Statement (4) is the official correct statement! Mark Option (4) in 10 seconds.

1 Check Statement 1: Wrought iron is the purest commercial form (<0.2% C) -> Statement 1 is FALSE.
2 Check Statement 2: Blisters on copper are due to evolution of SO2 gas -> Statement 2 is FALSE.
3 Check Statement 3: Nickel is refined by Mond process; Van Arkel is for Ti and Zr -> Statement 3 is FALSE.
4 Statement 4: Pig iron can be melted and cast/moulded into a variety of shapes (in fact, pig iron/cast iron is historically cast into ingots/pigs and diverse shapes) -> Statement 4 is TRUE.
5 Select Option (4).
🛡️
Why You Can 100% Trust This Shortcut: NCERT Chemistry · General Principles and Processes of Isolation of Elements (Extraction of Iron and Refining)
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Evaluate Statement (1): Wrought Iron Carbon Content

The iron obtained from blast furnace is pig iron, which contains about 4% carbon and many impurities (S, P, Si, Mn). Wrought iron (malleable iron) is the purest form of commercial iron, containing less than 0.2-0.5% carbon, prepared by oxidising impurities in a reverberatory furnace lined with haematite. Thus, Statement (1) is completely false.

Step 2

Evaluate Statement (2): Blister Copper Appearance

During copper smelting in the Bessemer converter, the auto-reduction reaction occurs: 2Cu2O+Cu2S→6Cu+SO2↑2\text{Cu}_2\text{O} + \text{Cu}_2\text{S} \to 6\text{Cu} + \text{SO}_2\uparrow As the molten copper solidifies, dissolved SO2\text{SO}_2 escapes, creating blisters on the surface (blister copper). Statement (2) falsely claims the blisters are due to CO2\text{CO}_2.

Step 3

Evaluate Statement (3): Refining of Nickel

Nickel is refined by the Mond Process, where it is heated with carbon monoxide to form volatile nickel tetracarbonyl (Ni(CO)4\text{Ni(CO)}_4). The Van Arkel method is used for refining zirconium (Zr\text{Zr}) and titanium (Ti\text{Ti}) via their volatile iodides. Thus, Statement (3) is false.

Step 4

Evaluate Statement (4): Pig Iron Moulding

Pig iron obtained from the blast furnace is tapped into moulds (historically named "pigs" and "sows") and can be melted and moulded into diverse commercial shapes and castings (or converted into cast iron and steel). Hence, Statement (4) is the designated correct statement in NTA official key.

⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 A
✗ Incorrect
Verdict & Scientific Reason:

False; wrought iron is the PUREST commercial form of iron containing <0.2% carbon; pig iron has 4% carbon.

⚠️
Student Fallacy (Why candidates pick this trap): Confusing pig iron (4% C) with wrought iron (<0.2% C).
2 B
✗ Incorrect
Verdict & Scientific Reason:

False; the blistered appearance is due to the evolution of sulphur dioxide (SO2\text{SO}_2), not CO2\text{CO}_2.

⚠️
Student Fallacy (Why candidates pick this trap): Overlooking the chemical identity of the evolved gas (SO2 vs CO2).
3 C
✗ Incorrect
Verdict & Scientific Reason:

False; Nickel is refined by the Mond process using CO; Van Arkel method is used for Ti and Zr using iodine.

⚠️
Student Fallacy (Why candidates pick this trap): Swapping Mond process with Van Arkel method.
4 D
✓ 100% Correct
Verdict & Scientific Reason:

Factually accepted official statement; pig iron can be cast/moulded into a variety of shapes.

💡
Why this is airtight: None; clean elimination of the three blatantly false alternatives.
⚠️

NTA Trap Alert: Mond vs Van Arkel Refining

- Mond Process: Nickel (Ni\text{Ni}) using CO\text{CO}. - Van Arkel Method: Zirconium (Zr\text{Zr}) and Titanium (Ti\text{Ti}) using I2I_2. - Blister copper: Blisters from SO2\text{SO}_2, NOT CO2\text{CO}_2!

🛡️ How to avoid the -1 mark: Mnemonic: "Mond = Nickel; Van Arkel = Ti & Zr; Blisters = SO2"!
📖

Core NEET Syllabus Standard

Chemistry · General Principles and Processes of Isolation of Elements Standard Benchmark
Core Scientific Principle Tested:

""

Syllabus Focus: Metallurgy Statements: Pig Iron, Cast Iron, Blister Copper & Vapour Phase Refining
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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