NEET 2026 Physics Question 14 Solution
Question
In a solar system, the time-period of revolution of a planet tracing a circular orbit of radius R is proportional to:
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In a solar system, the time-period of revolution of a planet tracing a circular orbit of radius R is proportional to:
Square of period is proportional to cube of radius
For a planet of mass m orbiting a star of mass M at radius R, gravitational attraction provides the necessary centripetal force:
Substitute omega = 2pi / T into the dynamic balance:
Take the square root of both sides to obtain the explicit power of R:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Applies to pendulum time period, not planetary orbits.
Canonical statement of Kepler's Third Law; confirmed by Official NTA Final Answer Key.
Areal velocity confusion.
Omitted square root.
Students frequently memorize "Kepler's law relates period and cube of radius" and hastily select R^3 without isolating the power of T.
"Kepler's Third Law (Law of Periods): The square of the time period of revolution of a planet is proportional to the cube of the semi-major axis of its orbit: T^2 = k * R^3."
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