NEET 2025 Physics Question 32 Solution
Question
A body weighs 48 N on the surface of the earth. The gravitational force experienced by the body due to the earth at a height equal to one-third the radius of the earth from its surface is:
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A body weighs 48 N on the surface of the earth. The gravitational force experienced by the body due to the earth at a height equal to one-third the radius of the earth from its surface is:
Distance from center r = R + R/3 = 4R/3 ⟹ g' = g / (4/3)² = (9/16) g ⟹ W' = 48 × (9/16) = 27 N!
Gravitational attraction acts from the center of mass of the Earth. At a height h above the surface, the distance from the center is:
On the surface, the force is W₀ = G M m / R² = 48 N. At height h, the force is:
Substitute W₀ = 48 N into the equation:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Incorrect. Corresponds to using approximation g' = g(1 - 2h/R) = 48(1 - 2/3) = 16 N, which is completely invalid for large h = R/3.
100% correct. Exact inverse-square law gives W' = 48 × (3/4)² = 27 N.
Incorrect. Obtained from linear depth formula g(1 - d/R) with d = R/3 (48 × 2/3 = 32 N), confusing altitude with depth!
Incorrect. Arbitrary distractor (48 × 3/4).
The formula g' = g(1 - 2h/R) is ONLY valid for h << R (e.g. h < 5% of R). Here h = R/3 (33% of R), for which the approximation gives 16 N (Option 1). Using the exact formula gives the true value 27 N!
"g' = g / (1 + h/R)² = GM / (R + h)²."
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