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The equivalent capacitance of the system shown in the following circuit is:
Two 3 μF in parallel add up to 3 + 3 = 6 μF! Then 3 μF in series with 6 μF gives (3 × 6) / (3 + 6) = 18 / 9 = 2 μF in 5 seconds!
Inspect the right branch of the circuit: two identical capacitors of capacitance 3 μF are connected in parallel across the same potential nodes. The equivalent capacitance of a parallel combination is the direct sum:
The parallel block C_p = 6 μF is connected in series with the first capacitor C_1 = 3 μF between terminals A and B. The equivalent series capacitance is given by the reciprocal formula:
Inverting yields the net equivalent capacitance:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Corresponds to all three capacitors in parallel (3 + 3 + 3 = 9 μF).
Accurate equivalent capacitance: 6 μF in series with 3 μF equals 2 μF.
Incorrect equivalent value.
Represents only the parallel stage, forgetting the series capacitor.
Capacitors combine opposite to resistors: capacitors ADD in parallel (C = C₁ + C₂) and take reciprocals in series (1/C = 1/C₁ + 1/C₂). Applying resistor rules yields wrong answers.
"Charge is identical in series (1/C_eq = Σ 1/C_i); voltage is identical in parallel (C_eq = Σ C_i)."
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