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Q.76 Chemistry ⭐ 360° Option Elimination Active
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NEET 2026 Chemistry Question 76 Solution

Topic: Hydrocarbons & Haloalkanes · Official NTA Booklet Code 50
NEET 2026 Chemistry Question 76: Stereospecific Electrophilic & Syn Additions to Alkenes (TAM & CSM Rules)

Question

Given below are two statements: Statement I: trans-But-2-ene upon treatment with Br₂ in CCl₄ gives the following product (Newman projection shown). Statement II: cis-But-2-ene upon treatment with alkaline KMnO₄ gives the following product (Newman projection shown). In the light of the above statements, choose the most appropriate answer from the options given below.

✓
Verified Against NTA Final Answer Key
Option (4) : Statement I is incorrect but Statement II is correct.
📚 Hydrocarbons & Haloalkanes Challenging
📋 Given Parameters & Problem Setup
Statement I trans-But-2-ene upon treatment with Br₂ in CCl₄ gives the depicted Newman projection
Statement II cis-But-2-ene upon treatment with alkaline KMnO₄ gives the depicted Newman projection
⚡

The 30-Second Exam Hall Shortcut: ⚡ Stereospecific Addition Mnemonics (TAM & CSM)

⏱️ Save ~90 seconds

TAM: Trans + Anti = Meso! CSM: Cis + Syn = Meso!

1 Bromination (Br₂/CCl₄) proceeds via cyclic bromonium ion with ANTI addition.
2 Apply TAM: Trans-alkene + Anti addition = MESO compound.
3 In the Newman projection of Statement I, both Me groups are on the right side while Br are opposite; this represents an optically active racemic/threo enantiomer, NOT the meso compound! -> Statement I is FALSE.
4 Alkaline KMnO₄ (Baeyer's reagent) proceeds via cyclic manganate ester with SYN addition.
5 Apply CSM: Cis-alkene + Syn addition = MESO compound.
6 In Statement II, the Newman projection has an internal plane of symmetry eclipsing identical groups (OH with OH, H with H, Me with Me), which IS the meso compound! -> Statement II is TRUE.
7 Statement I is incorrect but Statement II is correct -> Option (4)!
🛡️
Why You Can 100% Trust This Shortcut: Established stereochemical theorems: Anti-addition across trans-alkenes yields meso-2,3-dibromobutane; Syn-dihydroxylation of cis-alkenes yields meso-butane-2,3-diol.
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Analyze Statement I: Bromination of trans-But-2-ene

Addition of Br₂ across an alkene in non-polar CCl₄ proceeds through a cyclic bromonium ion intermediate, resulting in stereospecific ANTI addition. According to the stereochemical addition rule (TAM: Trans + Anti = Meso), bromination of trans-but-2-ene MUST produce MESO-2,3-dibromobutane.

trans-But-2-ene+Br2→Anti Additionmeso-2,3-dibromobutane\text{trans-But-2-ene} + \text{Br}_2 \xrightarrow{\text{Anti Addition}} \text{meso-2,3-dibromobutane}
  • • In meso-2,3-dibromobutane in its anti conformation, there is an inversion center: if front carbon has Br UP and Me DOWN-RIGHT, the back carbon must have Br DOWN and Me UP-LEFT.
  • • In the Newman projection given in Statement I, both Me groups are on the right and both H are on the left. Inverting through the center fails. This depicts the (2R, 3R) or (2S, 3S) chiral enantiomer (threo-pair), NOT the meso isomer!
  • • Statement I is incorrect.
Step 2

Analyze Statement II: Hydroxylation of cis-But-2-ene

Reaction of an alkene with cold, alkaline KMnO₄ (Baeyer's reagent) proceeds via a cyclic permanganate ester intermediate, delivering both hydroxyl groups to the SAME face of the double bond (SYN addition). According to the stereochemical addition rule (CSM: Cis + Syn = Meso), syn-dihydroxylation of cis-but-2-ene produces MESO-butane-2,3-diol.

cis-But-2-ene+alkaline KMnO4→Syn Additionmeso-butane-2,3-diol\text{cis-But-2-ene} + \text{alkaline KMnO}_4 \xrightarrow{\text{Syn Addition}} \text{meso-butane-2,3-diol}
  • • In the Newman projection in Statement II, the groups are in a near-eclipsed conformation where front OH aligns with back OH, front H aligns with back H, and front Me aligns with back Me.
  • • This eclipsed conformation contains an internal plane of symmetry (σ), which is the definitive visual hallmark of the meso isomer.
  • • Statement II is correct.
Step 3

Conclusion

Statement I is incorrect, but Statement II is correct.

Statement I: False,Statement II: True  ⟹  Option (4)\text{Statement I: False}, \quad \text{Statement II: True} \implies \text{Option (4)}
  • • Matches Option (4).
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 A
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. Statement I draws the racemic diastereomer instead of the meso isomer.

⚠️
Student Fallacy (Why candidates pick this trap): Failing to inspect the spatial configuration of the Newman projection in Statement I.
2 B
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. Statement II correctly depicts the meso diol formed by syn dihydroxylation.

⚠️
Student Fallacy (Why candidates pick this trap): Thinking KMnO₄ performs anti dihydroxylation.
3 C
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. Exactly backwards.

⚠️
Student Fallacy (Why candidates pick this trap): Confusing anti addition stereochemistry with syn addition stereochemistry.
4 D
✓ 100% Correct
Verdict & Scientific Reason:

Scientifically exact: Statement I fails because the depicted Newman structure is chiral threo, whereas Statement II correctly depicts the symmetric meso diol.

💡
Why this is airtight: None; mastery of stereochemical addition mechanisms.
⚠️

NTA Trap Alert: Looking Only at the Reaction Names Without Checking the Newman Projections

Students memorize "trans + Br₂ gives product, cis + KMnO₄ gives product" and assume both statements must be true (Option 1). They fail to check the actual Newman drawing, which deliberately depicts the WRONG stereoisomer for Statement I!

🛡️ How to avoid the -1 mark: Always test symmetry of Newman projections: For meso in anti-staggered conformation, identical groups must be diagonally opposite (center of inversion).
📖

Core NEET Syllabus Standard

NEET Chemistry Core Syllabus · Hydrocarbons Standard Benchmark
Core Scientific Principle Tested:

"Anti addition on trans-alkene yields meso; Syn addition on cis-alkene yields meso."

Syllabus Focus: Stereospecific addition reactions of alkenes - Bromination and Baeyer's oxidation
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗
TAM: Trans + Anti = Meso! CSM: Cis + Syn = Meso!

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