NEET 2024 Chemistry Question 98 Solution
Question
— The pair of lanthanoid ions which are diamagnetic is
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— The pair of lanthanoid ions which are diamagnetic is
Lanthanoid ions are diamagnetic ONLY when 4f is completely EMPTY (4f⁰, e.g. Ce⁴⁺, La³⁺) or completely FILLED (4f¹⁴, e.g. Yb²⁺, Lu³⁺)! Ce⁴⁺ and Yb²⁺ is the only diamagnetic pair!
Lanthanoids have valence electrons filling the 4f subshell, with neutral ground states: - Cerium (Ce, Z = 58): [Xe] 4f¹ 5d¹ 6s² - Ytterbium (Yb, Z = 70): [Xe] 4f¹⁴ 6s² - Europium (Eu, Z = 63): [Xe] 4f⁷ 6s² - Gadolinium (Gd, Z = 64): [Xe] 4f⁷ 5d¹ 6s²
Removing electrons from the outermost orbitals: 1. Ce⁴⁺: Loses 6s², 5d¹, and 4f¹ ⟹ [Xe] 4f⁰. Possesses an empty 4f subshell (n = 0 unpaired electrons) ⟹ Diamagnetic. 2. Yb²⁺: Loses 6s² ⟹ [Xe] 4f¹⁴. Possesses a completely filled 4f subshell (n = 0 unpaired electrons) ⟹ Diamagnetic. 3. Gd³⁺: Loses 6s² and 5d¹ ⟹ [Xe] 4f⁷ (n = 7 unpaired electrons) ⟹ Strongly paramagnetic. 4. Eu³⁺: Loses 6s² and one 4f ⟹ [Xe] 4f⁶ (n = 6 unpaired electrons) ⟹ Paramagnetic. 5. Eu²⁺: Loses 6s² ⟹ [Xe] 4f⁷ (n = 7 unpaired electrons) ⟹ Paramagnetic.
Ce⁴⁺ (4f⁰) and Yb²⁺ (4f¹⁴) both possess zero unpaired f-electrons. Consequently, both are diamagnetic, matching Option (3).
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Gd3+ has 7 unpaired electrons (4f7); Eu3+ has 6 unpaired electrons (4f6). Both are paramagnetic.
Pm3+ is 4f4 (n=4) and Sm3+ is 4f5 (n=5). Both are paramagnetic.
Ce4+ is 4f0 and Yb2+ is 4f14; both have zero unpaired electrons and are diamagnetic.
Ce3+ is 4f1 (n=1) and Eu2+ is 4f7 (n=7). Both are paramagnetic.
Students frequently associate "extra stability" of half-filled 4f7 with diamagnetism. 4f7 has SEVEN unpaired electrons, making it the MOST paramagnetic ion, not diamagnetic!
"Lanthanoid ions are diamagnetic only when they possess empty (4f0, e.g. Ce4+, La3+) or completely filled (4f14, e.g. Yb2+, Lu3+) f-orbitals."
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