NEET 2024 Chemistry Question 97 Solution
Question
— Identify the correct answer.
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Carbonate CO3²⁻ has 3 equivalent oxygen atoms sharing one double bond and two single bonds -> Exactly THREE canonical Lewis forms! Option (2) is TRUE!
In the carbonate ion (CO3²⁻), the carbon atom forms one double bond (C=O) and two single bonds (C-O⁻) with formal charges -1 on each single-bonded oxygen. Because all three oxygens are chemically and spatially equivalent, the double bond is delocalized equally among the three oxygen atoms, generating three equivalent canonical Lewis resonance structures:
Both NH3 and NF3 have trigonal pyramidal geometries with one lone pair. In NH3, nitrogen is more electronegative than hydrogen, so N-H bond dipoles reinforce the lone pair dipole: μ = 1.47 D. In NF3, fluorine is more electronegative than nitrogen, so N-F bond dipoles oppose the lone pair dipole, resulting in a tiny net dipole: μ = 0.24 D. Hence μ(NH3) > μ(NF3). Statement 1 is false.
Ozone (O3) is an angular molecule with a central oxygen atom bonded to two terminal oxygens. It possesses only TWO principal canonical resonance structures:
Boron trifluoride (BF3) has sp² hybridization and symmetrical trigonal planar geometry with 120° bond angles. The vector sum of the three identical B-F bond dipole moments is identically zero:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
False: μ(NH3) = 1.47 D > μ(NF3) = 0.24 D.
True: Carbonate has exactly 3 equivalent canonical Lewis resonance structures.
False: Ozone has only 2 principal canonical forms.
False: Trigonal planar symmetry cancels all bond dipoles to zero.
Even though fluorine is much more electronegative than hydrogen, in NF3 the bond dipoles oppose the lone pair, canceling most of the dipole. In NH3, they add constructively!
"Carbonate ion CO3 2- exhibits resonance among three equivalent canonical structures where the double bond is shared across each C-O bond."
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