MyCompetitiveExams Logo MyCompetitiveExams
MyCompetitiveExams Logo MyCompetitiveExams
Search 1,140+ Questions
Chapters, formulas, speed tricks
→
⚡ Brahmastra NEET 2027
720 MARKS

Dynamic 180-question full-length simulator mixed dynamically from all 6 years for 2027 & 2026 aspirants.

Launch Brahmastra 2027 Test →
Start Practice →
100% Free · No Login Required
Q.138 Botany ⭐ 360° Option Elimination Active
Vault ↗

NEET 2021 Botany Question 138 Solution

Topic: Morphology of Flowering Plants · Official NTA Booklet Code M1
NEET 2021 Botany Question 138: Floral Formulas: Fabaceae, Solanaceae, Liliaceae, and Brassicaceae

Question

Match Column - I with Column - II. Column - I Column - II (a) (i) Brassicaceae (b) (ii) Liliaceae (c) (iii) Fabaceae (d) (iv) Solanaceae Select the correct answer from the options given below. (a) (b) (c) (d)

  1. (1)(iii) (iv) (ii) (i)
  2. (2)(i) (ii) (iii) (iv)
  3. (3)(ii) (iii) (iv) (i)
  4. (4)(iv) (ii) (i) (iii)
✓
Verified Against NTA Final Answer Key
Option (1) : (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
📚 Morphology of Flowering Plants Easy
📋 Given Parameters & Problem Setup
Column I (Formulas) (a) Zygomorphic diadelphous, (b) Actinomorphic pentamerous bicarpellary, (c) Perianth trimerous tricarpellary, (d) Tetradynamous cruciform
Column II (Families) (i) Brassicaceae, (ii) Liliaceae, (iii) Fabaceae, (iv) Solanaceae
⚡

The 30-Second Exam Hall Shortcut: ⚡ Instant Floral Fingerprint Identification!

⏱️ Save ~20 seconds

Vexillary / diadelphous (K(5)C1+2+(2)A(9)+1K_{(5)} C_{1+2+(2)} A_{(9)+1}) = Fabaceae (a-iii); Epipetalous pentamerous (C(5)A5C_{(5)} A_5) = Solanaceae (b-iv); Perianth (P(3+3)A3+3P_{(3+3)} A_{3+3}) = Liliaceae (c-ii); Tetradynamous cruciform (K2+2C4A2+4K_{2+2} C_4 A_{2+4}) = Brassicaceae (d-i)! Matches Option (1)!

1 (a) % indicates zygomorphic; C1+2+(2)A(9)+1G1  ⟹  C_{1+2+(2)} A_{(9)+1} G_1 \implies Fabaceae (iii).
2 (b) ⊕\oplus actinomorphic, K(5)C(5)A⏞5G(2)  ⟹  K_{(5)} \overbrace{C_{(5)} A}_5 G_{(2)} \implies Solanaceae (iv).
3 (c) Perianth P(3+3)A⏞3+3G(3)  ⟹  P_{(3+3)} \overbrace{A}_{3+3} G_{(3)} \implies Liliaceae (ii).
4 (d) K2+2C4A2+4G(2)  ⟹  K_{2+2} C_4 A_{2+4} G_{(2)} \implies Brassicaceae (Cruciferae) (i).
5 Match Option (1).
🛡️
Why You Can 100% Trust This Shortcut: Canonical NCERT Morphology of Flowering Plants on Semi-Technical Description of Families.
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Deconstruction of Diagnostic Floral Formulas

Each angiosperm family in the NCERT syllabus possesses unambiguous diagnostic floral characteristics:

(a) %  K(5)C1+2+(2)A(9)+1G‾1⟷Fabaceae (Papilionoideae)  ⟹  (iii)(b) ⊕  K(5)C(5)A5⏞G‾(2)⟷Solanaceae (Potato family)  ⟹  (iv)(c) ⊕  P(3+3)A3+3⏞G‾(3)⟷Liliaceae (Lily family)  ⟹  (ii)(d) ⊕  K2+2C4A2+4G‾(2)⟷Brassicaceae (Mustard family)  ⟹  (i)\begin{aligned} \text{(a) } \% \; \text{K}_{(5)} \text{C}_{1+2+(2)} \text{A}_{(9)+1} \underline{\text{G}}_1 & \longleftrightarrow \text{\textbf{Fabaceae (Papilionoideae)}} \implies \text{(iii)} \\[4pt] \text{(b) } \oplus \; \text{K}_{(5)} \overbrace{\text{C}_{(5)} \text{A}_5} \underline{\text{G}}_{(2)} & \longleftrightarrow \text{\textbf{Solanaceae (Potato family)}} \implies \text{(iv)} \\[4pt] \text{(c) } \oplus \; \overbrace{\text{P}_{(3+3)} \text{A}_{3+3}} \underline{\text{G}}_{(3)} & \longleftrightarrow \text{\textbf{Liliaceae (Lily family)}} \implies \text{(ii)} \\[4pt] \text{(d) } \oplus \; \text{K}_{2+2} \text{C}_4 \text{A}_{2+4} \underline{\text{G}}_{(2)} & \longleftrightarrow \text{\textbf{Brassicaceae (Mustard family)}} \implies \text{(i)} \end{aligned}
Step 2

Option Alignment

Matching (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i) directly and exclusively points to Option (1).

⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 1
✓ 100% Correct
Verdict & Scientific Reason:

Exact diagnostic alignment of all 4 botanical family floral formulas.

💡
Why this is airtight: None. Flawless knowledge of floral formulas.
2 2
✗ Incorrect
Verdict & Scientific Reason:

Mismatches Fabaceae with Brassicaceae and Solanaceae with Liliaceae.

⚠️
Student Fallacy (Why candidates pick this trap): Random assignment.
3 3
✗ Incorrect
Verdict & Scientific Reason:

Mismatches Fabaceae with Liliaceae and Solanaceae with Fabaceae.

⚠️
Student Fallacy (Why candidates pick this trap): Confusing monocot perianth with dicot zygomorphy.
4 4
✗ Incorrect
Verdict & Scientific Reason:

Mismatches Fabaceae with Solanaceae and Brassicaceae with Fabaceae.

⚠️
Student Fallacy (Why candidates pick this trap): Conflating pentamerous with papilionaceous symmetry.
⚠️

NTA Trap Alert: Perianth (P) vs Calyx/Corolla (K/C) Distinction

The presence of Perianth (P) immediately identifies the monocot family Liliaceae! Looking for P first saves immense time.

🛡️ How to avoid the -1 mark: Identify P(3+3)  ⟹  P_{(3+3)} \implies Liliaceae instantly.
📖

Core NEET Syllabus Standard

NEET / NCERT Biology · Morphology of Flowering Plants Standard Benchmark
Core Scientific Principle Tested:

"Fabaceae exhibits diadelphous papilionaceous corolla; Solanaceae exhibits epipetalous pentamerous flowers; Liliaceae exhibits perianth; Brassicaceae exhibits tetradynamous stamens."

Syllabus Focus: Description of Some Important Families
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

Ready to attempt under real exam pressure?

Test your speed and accuracy in the authentic 200-minute timed NTA simulator.

Launch NEET 2021 CBT Test →

Spotted a mistake in this solution? Report an error ([email protected])

⚖️ Legal & Fair Dealing Notice: Sourced from publicly released NEET 2021 question papers and NEET answer keys for private study, research, and non-commercial educational practice under Fair Dealing (Section 52(1)(a) of the Indian Copyright Act, 1957). Not affiliated with or endorsed by NTA or NMC.

Solve 4 NEET Questions a Day — One per Subject

Cover all 1,140 official NEET questions in 285 days at your own pace. Progress is saved on your device. No login needed.