NEET 2024 Physics Question 13 Solution
Question
The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is 2400 g cm². The length of the 400 g rod is nearly:
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The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is 2400 g cm². The length of the 400 g rod is nearly:
I = ML² / 12 -> L² = 12 I / M = 12 × 2400 / 400 = 12 × 6 = 72 -> L = √72 ≈ 8.485 cm ≈ 8.5 cm!
For a uniform thin straight rod of mass M and length L, the moment of inertia about an axis perpendicular to the rod and passing through its center of mass (midpoint) is given by integration as:
Substituting the given values I = 2400 g cm² and M = 400 g directly into the formula (in CGS units):
Simplifying the equation:
Taking the square root of 72:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Incorrect; would occur if formula for rod about one end (I = ML²/3) was used with incorrect algebra.
Confuses L² (72 cm²) with L (8.5 cm), forgetting to take the square root!
Exact root of L² = 72 cm²: L = 8.485 cm ≈ 8.5 cm.
Approximately double the correct length.
NTA intentionally included 72.0 cm as Option (2) because students calculate L² = 72 and instinctively bubble it without taking the square root.
"The moment of inertia of a uniform rod of mass M and length L about its central transverse axis is I = ML²/12."
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