NEET 2024 Physics Question 14 Solution
Question
In a vernier calipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is:
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In a vernier calipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is:
LC = 1 MSD - 1 VSD = 1 MSD / (N + 1); 0.1 mm = 0.01 cm = 1/100 cm -> LC = 1 / [100(N + 1)] cm!
The Vernier Constant (also known as the Least Count) of a Vernier caliper is the difference between the length of one main scale division (MSD) and one vernier scale division (VSD):
We are given that (N + 1) divisions of the vernier scale coincide with N divisions of the main scale:
Substituting 1 VSD into the definition of VC:
We are given 1 MSD = 0.1 mm. Expressing this in centimeters:
Substituting 1 MSD = 1/100 cm into the VC equation:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Dimensionally invalid for least count.
Dimensionally invalid.
Incorrect denominator factor and missing (N + 1).
Exact derivation: 1 MSD / (N + 1) with 1 MSD = 1/100 cm.
The question explicitly asks for the vernier constant in cm, whereas 1 MSD is given in mm. Forgetting to divide by 10 leads to 1 / [10(N + 1)].
"Least Count = 1 MSD - 1 VSD = (1 MSD) / (Number of vernier divisions)."
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