NEET 2023 Physics Question 8 Solution
Question
An ac source is connected to a capacitor C. Due to decrease in its operating frequency:
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An ac source is connected to a capacitor C. Due to decrease in its operating frequency:
Lower frequency means higher capacitive reactance (X_C = 1/ωC ↑), so current drops (I = V/X_C ↓); displacement current equals conduction current, so it decreases!
The opposition offered by a capacitor to alternating current is capacitive reactance X_C:
When the operating frequency f decreases, the capacitive reactance X_C increases inversely:
The alternating current in the circuit (conduction current i_c) is determined by Ohm's law in AC circuits:
Inside the capacitor plates, the changing electric flux generates displacement current i_d, which identically equals the conduction current i_c at every instant:
Since f decreases, i_d decreases proportionally:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
False. X_C depends inversely on frequency (X_C = 1/(2πfC)).
False. As frequency decreases, X_C increases, not decreases.
False. Since impedance increases, current decreases.
Accurate deduction: lower frequency causes higher reactance, lowering both conduction and displacement currents.
Some students treat displacement current as an abstract quantity separate from circuit current. In reality, i_d is continuous with conduction current i_c.
"Capacitive current i = V/(X_C) = 2π f C V. Decreasing frequency reduces current directly."
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