NEET 2023 Physics Question 6 Solution
Question
In hydrogen spectrum, the shortest wavelength in the Balmer series is λ. The shortest wavelength in the Bracket series is:
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In hydrogen spectrum, the shortest wavelength in the Balmer series is λ. The shortest wavelength in the Bracket series is:
For shortest wavelength (n₂ = ∞), λ ∝ n₁²! Balmer has n₁=2 (2²=4), Brackett has n₁=4 (4²=16); 16/4 = 4 → λ_Brackett = 4λ in 5 seconds!
The wavelength λ of radiation emitted during an electronic transition from state n₂ to state n₁ in hydrogen is given by the Rydberg formula:
The shortest wavelength corresponds to the maximum energy transition, which occurs from n₂ = ∞ to the ground level of that series (n₁):
For the Balmer series, n₁ = 2. For the Brackett series, n₁ = 4:
Substitute 1/R into the expression for Brackett series limit:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Overestimates by a factor of 4.
Linearly scales with n₁ instead of quadratic scaling.
Exact ratio derived from quadratic series limit scaling (16 / 4 = 4).
Corresponds to Paschen series limit relative to a different reference.
Aspirants frequently forget that energy levels follow 1/n² while wavelengths scale with n₁² for series limits. Scaling linearly (4/2 = 2) leads directly to the trap Option (2).
"Lyman (1), Balmer (2), Paschen (3), Brackett (4), Pfund (5). For shortest wavelength, λ_min ∝ n₁²."
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