NEET 2023 Chemistry Question 92 Solution
Question
Identify the major product obtained in the following reaction: 2-acetylbenzaldehyde + 2[Ag(NH₃)₂]⁺ + 3 ⁻OH → (Δ) major product
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Identify the major product obtained in the following reaction: 2-acetylbenzaldehyde + 2[Ag(NH₃)₂]⁺ + 3 ⁻OH → (Δ) major product
Tollens’ reagent [Ag(NH₃)₂]⁺ is a mild, selective oxidizing agent that oxidizes aldehydes (–CHO ⟶ –COO⁻) but cannot oxidize ketones! Therefore, the –CHO group becomes –COO⁻, and the –COCH₃ group remains 100% intact. Option (4) is immediately selected in 5 seconds!
The reactant is 2-acetylbenzaldehyde, containing two different carbonyl functional groups on adjacent positions of a benzene ring: an aldehyde (–CHO) and a methyl ketone (–COCH₃):
Ammoniacal silver nitrate solution [Ag(NH₃)₂]⁺ in the presence of base (OH⁻) is Tollens’ reagent, a classic mild oxidizing agent:
Tollens’ reagent readily oxidizes the formyl group (–CHO) to the corresponding carboxylate anion (–COO⁻) while metallic silver is precipitated as a silver mirror:
Under these mild basic oxidizing conditions, ketones do not have an oxidizable hydrogen atom on the carbonyl carbon and remain completely unreacted. The –COCH₃ group persists unchanged in the product:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
The ketone is not reduced under Tollens’ oxidation conditions.
Neither group undergoes reduction; Tollens’ is an oxidizing agent, not a reducing hydride.
Aldehyde is oxidized to carboxylate, not reduced to primary alcohol.
Accurate: Chemoselective oxidation of aldehyde to carboxylate while ketone remains completely intact.
Some students see [Ag(NH₃)₂]⁺ and confuse it with complex metal hydrides (NaBH₄ or LiAlH₄), mistakenly drawing reduced alcohol groups. Tollens’ is an OXIDIZING agent that converts –CHO to –COO⁻.
"Tollens’ reagent selectively oxidizes aldehydes to carboxylate anions without affecting ketonic carbonyls."
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