NEET 2025 Chemistry Question 70 Solution
Question
The correct order of decreasing acidity of the following aliphatic acids is:
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The correct order of decreasing acidity of the following aliphatic acids is:
Acidity ∝ 1 / (+I effect)! Alkyl groups push electron density into -COO⁻, destabilizing the conjugate base and reducing acidity! HCOOH has zero alkyl groups (STRONGEST). CH₃ has 1 methyl. (CH₃)₂CH has 2 methyls. (CH₃)₃C has 3 methyls (WEAKEST)! ⟹ HCOOH > CH₃COOH > (CH₃)₂CHCOOH > (CH₃)₃CCOOH!
Carboxylic acids dissociate in water to generate carboxylate anions and hydronium ions:
Alkyl groups are electron-releasing (+I) groups. As the size and branching of the alkyl group increases, its +I electron-donating power increases dramatically:
Invert the +I hierarchy to obtain the decreasing acidity series:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Incorrect. Completely inverts the acidity order, treating +I groups as acid-strengthening.
Incorrect. Falsely places formic acid (HCOOH) as the weakest acid.
100% correct. HCOOH is strongest, followed by acetic, isobutyric, and pivalic acid.
Incorrect. Scrambled middle order.
Some students memorize that substituted acids can be stronger and mistakenly think CH₃COOH is stronger than HCOOH. In reality, HCOOH is significantly stronger than acetic acid (pK_a 3.75 vs 4.76) because H does not donate electrons by +I effect!
"+I electron donating groups decrease acidity: HCOOH > CH₃COOH > R₂CHCOOH > R₃CCOOH."
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