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Q.64 Chemistry ⭐ 360° Option Elimination Active
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NEET 2023 Chemistry Question 64 Solution

Topic: Aldehydes, Ketones and Carboxylic Acids · Official NTA Booklet Code G5
NEET 2023 Chemistry Question 64: Cyanohydrin Formation, Acidic Hydrolysis, and Dehydration to α,β-Unsaturated Acid

Question

Complete the following reaction: Cyclohexanone [A] → (HCN) 1-hydroxycyclohexane-1-carbonitrile [B] → (conc. H₂SO₄, Δ) [C]. [C] is ___.

✓
Verified Against NTA Final Answer Key
Option (1) : Cyclohex-1-enecarboxylic acid
📚 Aldehydes, Ketones and Carboxylic Acids Medium
📋 Given Parameters & Problem Setup
Substrate [A] Cyclohexanone
Reagent 1 HCN (Nucleophilic addition)
Intermediate [B] 1-Hydroxycyclohexanecarbonitrile (Cyanohydrin)
Reagent 2 Conc. H₂SO₄, heat (Hydrolysis + Dehydration)
⚡

The 30-Second Exam Hall Shortcut: ⚡ Dual Transformation Hack: -CN ⟶ -COOH and -OH ⟶ C=C

⏱️ Save ~45 seconds

HCN adds to cyclohexanone to form cyanohydrin [B]. Hot conc. H₂SO₄ accomplishes TWO things at once: hydrolyzes -CN to -COOH AND dehydrates -OH to an endocyclic double bond ⟹ Cyclohex-1-enecarboxylic acid in 15 seconds!

1 Step 1: Nucleophilic addition of HCN across the carbonyl group of cyclohexanone yields 1-hydroxycyclohexanecarbonitrile (cyanohydrin [B]).
2 Step 2: Reaction with hot concentrated sulfuric acid (conc. H₂SO₄, Δ) causes two simultaneous reactions:
3 - Acidic hydrolysis: The nitrile group -CN is completely hydrolyzed into a carboxylic acid group -COOH.
4 - Acid-catalyzed dehydration: Conc. H₂SO₄ is a powerful dehydrating agent that removes the tertiary -OH group and an adjacent ring α-hydrogen (H₂O loss) to form a conjugated C=C double bond.
5 The product is an α,β-unsaturated carboxylic acid: cyclohex-1-enecarboxylic acid.
6 Lock Option (1) immediately!
🛡️
Why You Can 100% Trust This Shortcut: Organic Reaction Mechanisms · Nitrile Hydrolysis and Alcohol Dehydration (Conc. H₂SO₄ with heat simultaneously converts nitriles into carboxylic acids and secondary/tertiary alcohols into alkenes).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Nucleophilic Addition of HCN to Cyclohexanone (Formation of [B])

Cyanide ion (:CN⁻) attacks the electrophilic carbonyl carbon of cyclohexanone, followed by protonation of the alkoxide intermediate to yield the cyanohydrin, 1-hydroxycyclohexanecarbonitrile [B]:

C6H10O+HCN⟶C6H10(OH)(CN)(Intermediate [B])\text{C}_6\text{H}_{10}\text{O} + \text{HCN} \longrightarrow \text{C}_6\text{H}_{10}(\text{OH})(\text{CN}) \quad (\text{Intermediate }[B])
Step 2

Acidic Hydrolysis of the Nitrile Functionality

In the presence of concentrated sulfuric acid and water at elevated temperature, the nitrile group undergoes complete hydrolysis through an amide intermediate to a carboxylic acid (-COOH):

−C≡N+2H2O+H+→Δ−COOH+NH4+-\text{C}\equiv\text{N} + 2\text{H}_2\text{O} + \text{H}^+ \xrightarrow{\Delta} -\text{COOH} + \text{NH}_4^+
Step 3

Acid-Catalyzed Dehydration by Concentrated H₂SO₄

Under the hot, strongly acidic conditions of concentrated H₂SO₄, the tertiary alcohol hydroxyl group is protonated to form -OH₂⁺ and departs. Concurrently, a proton is eliminated from an adjacent ring carbon (C-2) to yield a thermodynamically stabilized α,β-unsaturated carboxylic acid:

C6H10(OH)(COOH)→conc. H2SO4, ΔCyclohex-1-enecarboxylic acid+H2O\text{C}_6\text{H}_{10}(\text{OH})(\text{COOH}) \xrightarrow{\text{conc. } \text{H}_2\text{SO}_4, \, \Delta} \text{Cyclohex-1-enecarboxylic acid} + \text{H}_2\text{O}
Step 4

Identification of Final Product [C]

The structure of product [C] consists of a cyclohexene ring with the carboxylic acid group directly attached to the sp²-hybridized alkene carbon, matching Option (1).

[C]=Cyclohex-1-enecarboxylic acid[C] = \text{Cyclohex-1-enecarboxylic acid}
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 (1)
✓ 100% Correct
Verdict & Scientific Reason:

Accurate product resulting from both nitrile hydrolysis to -COOH and ring dehydration to an alkene.

💡
Why this is airtight: None. Candidate accounted for both hydrolysis and dehydration.
2 (2)
✗ Incorrect
Verdict & Scientific Reason:

Corresponds to simple reduction of cyclohexanone, completely ignoring HCN and H₂SO₄.

⚠️
Student Fallacy (Why candidates pick this trap): Wild guess unrelated to the chemical reagents.
3 (3)
✗ Incorrect
Verdict & Scientific Reason:

Saturated acid: assumes hydrolysis occurred but dehydration of -OH was overlooked.

⚠️
Student Fallacy (Why candidates pick this trap): Candidate forgot that hot concentrated H₂SO₄ is a powerful dehydrating agent that eliminates -OH.
4 (4)
✗ Incorrect
Verdict & Scientific Reason:

Contains an aldehyde (-CHO) group instead of a carboxylic acid (-COOH).

⚠️
Student Fallacy (Why candidates pick this trap): Candidate confused full acidic hydrolysis of nitrile with partial DIBAL-H reduction.
⚠️

NTA Trap Alert: Forgetting Dehydration by Concentrated Sulfuric Acid

Many candidates remember that nitriles hydrolyze to carboxylic acids, but forget that CONCENTRATED H₂SO₄ WITH HEAT is a classic dehydrating agent. Overlooking dehydration leads to picking saturated cyclohexanecarboxylic acid (Option 3).

🛡️ How to avoid the -1 mark: Whenever you see "conc. H₂SO₄ + Δ" with an alcohol, eliminate water to form an alkene!
📖

Core NEET Syllabus Standard

National Eligibility cum Entrance Test (NEET UG) · Aldehydes, Ketones and Carboxylic Acids Standard Benchmark
Core Scientific Principle Tested:

"Cyanohydrins undergo acid hydrolysis to give α-hydroxy acids, which readily undergo dehydration under hot conc. H₂SO₄ to give α,β-unsaturated acids."

Syllabus Focus: Reactions of Carbonyl Compounds – Cyanohydrin Formation and Reactions
Preserved in Rationalized Curriculum Syllabus & Academic Standards ↗

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