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Q.14 Physics ⭐ 360° Option Elimination Active
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NEET 2021 Physics Question 14 Solution

Topic: Nuclei · Official NTA Booklet Code M1
NEET 2021 Physics Question 14: Radioactive Decay Law: Alpha, Beta-Minus, and Beta-Plus (Positron) Emissions

Question

A radioactive nucleus ᴬ_ZX undergoes spontaneous decay in the sequence ᴬ_ZX → Z−1B → Z−3C → Z−2D, where Z is the atomic number of element X. The possible decay particles in the sequence are:

✓
Verified Against NTA Final Answer Key
Option (3) : β+, α, β-
📚 Nuclei Easy
📋 Given Parameters & Problem Setup
Decay Step 1 {}_Z^A X -> {}_{Z-1} B (ΔZ = -1)
Decay Step 2 {}_{Z-1} B -> {}_{Z-3} C (ΔZ = -2)
Decay Step 3 {}_{Z-3} C -> {}_{Z-2} D (ΔZ = +1)
⚡

The 30-Second Exam Hall Shortcut: ⚡ ΔZ Tracker: -1 is β+, -2 is α, +1 is β-

⏱️ Save ~20 seconds

Track the change in atomic number Z at each decay step: 1. Z→Z−1Z \to Z-1 (DeltaZ=−1\\Delta Z = -1)   ⟹  β+\implies \beta^+ decay! 2. Z−1→Z−3Z-1 \to Z-3 (DeltaZ=−2\\Delta Z = -2)   ⟹  α\implies \alpha decay! 3. Z−3→Z−2Z-3 \to Z-2 (DeltaZ=+1\\Delta Z = +1)   ⟹  β−\implies \beta^- decay! The sequence is β+,α,β−\beta^+, \alpha, \beta^-! Match Option (3)!

1 Step 1: Atomic number decreases by 1 (Z→Z−1Z \to Z-1)   ⟹  \implies positron emission (β+\beta^+ decay).
2 Step 2: Atomic number decreases by 2 (Z−1→Z−3Z-1 \to Z-3)   ⟹  \implies alpha particle emission (α\alpha decay).
3 Step 3: Atomic number increases by 1 (Z−3→Z−2Z-3 \to Z-2)   ⟹  \implies electron emission (β−\beta^- decay).
4 Sequence of emitted particles: β+,α,β−\beta^+, \alpha, \beta^-.
5 Match Option (3).
🛡️
Why You Can 100% Trust This Shortcut: Canonical nuclear charge conservation in radioactive alpha and beta decay.
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Conservation of Nuclear Charge (Atomic Number Z)

In all nuclear reactions, the total electric charge (atomic number ZZ) is strictly conserved. Let ΔZ\Delta Z be the change in atomic number of the daughter nucleus relative to the parent nucleus.

Step 2

Analyzing Step 1: X -> B

The atomic number changes from ZZ to Z−1Z-1 (decreases by 1). This occurs when a proton converts into a neutron, emitting a positron (β+\beta^+):

ZAX⟶Z−1AB++10e(β+)+νe  ⟹  β+ decay{}_Z^A X \longrightarrow {}_{Z-1}^A B + {}_{+1}^0 e (\beta^+) + \nu_e \implies \mathbf{\beta^+\text{ decay}}
Step 3

Analyzing Step 2: B -> C

The atomic number changes from Z−1Z-1 to Z−3Z-3 (decreases by 2). This occurs when an alpha particle (24He{}_2^4\text{He}) is emitted:

Z−1AB⟶Z−3A−4C+24He(α)  ⟹  α decay{}_{Z-1}^A B \longrightarrow {}_{Z-3}^{A-4} C + {}_2^4\text{He} (\alpha) \implies \mathbf{\alpha\text{ decay}}
Step 4

Analyzing Step 3: C -> D

The atomic number changes from Z−3Z-3 to Z−2Z-2 (increases by 1). This occurs when a neutron converts into a proton, emitting an electron (β−\beta^-):

Z−3A−4C⟶Z−2A−4D+−10e(β−)+νˉe  ⟹  β− decay{}_{Z-3}^{A-4} C \longrightarrow {}_{Z-2}^{A-4} D + {}_{-1}^0 e (\beta^-) + \bar{\nu}_e \implies \mathbf{\beta^-\text{ decay}}
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 1
✗ Incorrect
Verdict & Scientific Reason:

Starts with alpha decay (which would reduce ZZ by 2 to Z−2Z-2, not Z−1Z-1).

⚠️
Student Fallacy (Why candidates pick this trap): Assuming α\alpha decay is always the first step in a decay chain.
2 2
✗ Incorrect
Verdict & Scientific Reason:

Incorrect first step (α\alpha instead of β+\beta^+).

⚠️
Student Fallacy (Why candidates pick this trap): Misreading ΔZ=−1\Delta Z = -1 as an alpha decay.
3 3
✓ 100% Correct
Verdict & Scientific Reason:

Exact match with the nuclear charge changes: ΔZ=−1\Delta Z = -1 (β+\beta^+), ΔZ=−2\Delta Z = -2 (α\alpha), ΔZ=+1\Delta Z = +1 (β−\beta^-).

💡
Why this is airtight: None; rigorous nuclear bookkeeping.
4 4
✗ Incorrect
Verdict & Scientific Reason:

Inverts β−\beta^- and β+\beta^+: β−\beta^- increases ZZ by 1, which would produce Z+1Z+1, not Z−1Z-1.

⚠️
Student Fallacy (Why candidates pick this trap): Confusing β−\beta^- with β+\beta^+ charge changes.
⚠️

NTA Trap Alert: Beta-Plus vs. Beta-Minus Sign Confusion Trap

Students frequently remember "beta decay changes Z by 1" and mix up the signs: β−\beta^- emission INCREASES ZZ by 1 (n→p+e−n \to p + e^-), while β+\beta^+ emission DECREASES ZZ by 1 (p→n+e+p \to n + e^+).

🛡️ How to avoid the -1 mark: ΔZ=−1  ⟹  β+\Delta Z = -1 \implies \beta^+ (positron). ΔZ=+1  ⟹  β−\Delta Z = +1 \implies \beta^- (electron). ΔZ=−2  ⟹  α\Delta Z = -2 \implies \alpha.
📖

Core NEET Syllabus Standard

NCERT Physics · Nuclei Standard Benchmark
Core Scientific Principle Tested:

"In α\alpha-decay, ZZ decreases by 2; in β+\beta^+-decay, ZZ decreases by 1; in β−\beta^--decay, ZZ increases by 1."

Syllabus Focus: Radioactivity (Alpha and Beta Decay)
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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