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Q.164 Physics ⭐ 360° Option Elimination Active
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NEET 2020 Physics Question 164 Solution

Topic: Current Electricity · Official NTA Booklet Code E1
NEET 2020 Physics Question 164: Carbon Resistor Color Coding: Resistance and Tolerance Determination

Question

The color code of a resistance is given below: The values of resistance and tolerance, respectively, are:

✓
Verified Against NTA Final Answer Key
Option (4) : 470 Ohm, 5%
📚 Current Electricity Easy
📋 Given Parameters & Problem Setup
Band 1 Yellow (digit 4)
Band 2 Violet (digit 7)
Band 3 Brown (multiplier 10^1)
Band 4 Gold (tolerance ±5%)
⚡

The 30-Second Exam Hall Shortcut: ⚡ "BB ROY: Yellow = 4, Violet = 7, Brown = ×10^1, Gold = ±5% => 47 × 10^1 = 470 Ω, 5%!"

⏱️ 20 seconds

Using the standard mnemonic 'B B ROY of Great Britain had a Very Good Wife': Yellow corresponds to 4, Violet corresponds to 7, Brown corresponds to multiplier 10^1, and Gold corresponds to ±5% tolerance. Value = 47 × 10^1 Ω = 470 Ω with 5% tolerance. Direct 5-second match with Option (4)!

1 1st band (Yellow) = 4.
2 2nd band (Violet) = 7.
3 3rd band (Brown) = multiplier 10110^1.
4 Resistance = 47×101 Ω=470 Ω47 \times 10^1\ \Omega = 470\ \Omega.
5 4th band (Gold) = ±5%\pm 5\% tolerance.
6 Select Option (4) 470 Ω, 5%.
🛡️
Why You Can 100% Trust This Shortcut: NCERT Physics · Current Electricity (Resistors: Color Coding)
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Review Carbon Resistor Color Coding System

For a 4-band carbon composition resistor: - First band: First significant decimal digit - Second band: Second significant decimal digit - Third band: Decimal multiplier (10n10^n) - Fourth band: Tolerance in percentage

Step 2

Decode Bands Sequentially

- Band 1 is Yellow: Value = 4 - Band 2 is Violet: Value = 7 - Combined significant figures: 47 - Band 3 is Brown: Multiplier = 10110^1 - Band 4 is Gold: Tolerance = ±5%\pm 5\% (Silver would be ±10%\pm 10\%, None would be ±20%\pm 20\%).

Step 3

Calculate Resistance Value

R=(47)×101 Ω=470 ΩR = (47) \times 10^1\ \Omega = 470\ \Omega. Tolerance = ±5%\pm 5\%.

Step 4

Match with Options

Option 4 explicitly specifies 470 Ω,5%470\ \Omega, 5\%.

⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 A
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; confuses Brown multiplier (10^1) with Yellow (10^4), giving 470 kilo-ohms.

⚠️
Student Fallacy (Why candidates pick this trap): Adding kilo-ohm prefix mistakenly.
2 B
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; confuses multiplier with Orange (10^3) and tolerance with Silver (10%).

⚠️
Student Fallacy (Why candidates pick this trap): Misremembering multiplier and tolerance bands.
3 C
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; confuses Brown multiplier (10^1) with Red (10^2), yielding 47 × 100 = 4700 Ω = 4.7 kΩ.

⚠️
Student Fallacy (Why candidates pick this trap): Off by a factor of 10 on the multiplier band.
4 D
✓ 100% Correct
Verdict & Scientific Reason:

Accurate value; Yellow (4), Violet (7), Brown (×10^1), Gold (±5%) gives 470 Ω, 5%.

💡
Why this is airtight: None; exact application of color code tables.
⚠️

NTA Trap Alert: Brown vs Black Multiplier

Black is 0 (multiplier 10^0 = 1). Brown is 1 (multiplier 10^1 = 10). Red is 2 (multiplier 10^2 = 100).

🛡️ How to avoid the -1 mark: Recite: Black (0), Brown (1), Red (2), Orange (3), Yellow (4), Green (5), Blue (6), Violet (7), Gray (8), White (9).
📖

Core NEET Syllabus Standard

Physics · Current Electricity Standard Benchmark
Core Scientific Principle Tested:

""

Syllabus Focus: Carbon Resistor Color Coding: Resistance and Tolerance Determination
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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