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Q.60 Chemistry · Section A ⭐ 360° Option Elimination Active
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NEET 2024 Chemistry Question 60 Solution

Topic: Chemical Kinetics · Official NTA Booklet Code T1
NEET 2024 Chemistry Question 60: Arrhenius Plot of ln k versus 1/T

Question

Which plot of ln k vs 1/T is consistent with Arrhenius equation?

✓
Verified Against NTA Final Answer Key
Option (2) : Plot (2): Straight line with negative slope and positive intercept
📚 Chemical Kinetics Easy
📋 Given Parameters & Problem Setup
Plotted function ln k on y-axis versus (1 / T) on x-axis
Theoretical basis Arrhenius equation: k = A e^(-E_a / RT)
⚡

The 30-Second Exam Hall Shortcut: ⚡ Arrhenius Slope Identification

⏱️ Save ~30 seconds

ln k = ln A - (E_a / R)(1/T) -> y = c + mx where slope m = -E_a/R is STRICTLY NEGATIVE -> Straight line sloping downward!

1 Linear form of Arrhenius equation: ln k = ln A - (E_a / R) · (1/T).
2 Match to standard straight line y = mx + c:
3 y = ln k, x = 1/T, Intercept c = ln A > 0, Slope m = -E_a / R < 0.
4 Because E_a > 0 and R > 0, the slope is negative: as 1/T increases (temperature cools), ln k decreases.
5 Plot (2) is the only plot showing a downward-sloping straight line with negative slope.
6 Option (2) in under 3 seconds!
🛡️
Why You Can 100% Trust This Shortcut: NCERT Chemistry · Chemical Kinetics (Arrhenius equation and determination of activation energy from graphical slope: Slope = -E_a / R).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Derivation of the Linear Equation

Taking the natural logarithm of both sides of the Arrhenius rate expression:

k=Ae−EaRT  ⟹  ln⁡k=ln⁡A−EaR(1T)k = A e^{-\frac{E_a}{RT}} \implies \ln k = \ln A - \frac{E_a}{R}\left(\frac{1}{T}\right)
Step 2

Comparison with Standard Linear Form y = mx + c

Aligning variables to identify graphical features: - Dependent variable: y = ln k - Independent variable: x = 1 / T - Slope: m = -Ea / R (strictly negative) - Y-intercept: c = ln A (positive finite value when extrapolated to 1/T = 0)

y=mx+c  ⟺  ln⁡k=(−EaR)⏟Slope <0(1T)+ln⁡A⏟Intercepty = mx + c \iff \ln k = \underbrace{\left(-\frac{E_a}{R}\right)}_{\text{Slope } < 0} \left(\frac{1}{T}\right) + \underbrace{\ln A}_{\text{Intercept}}
Step 3

Graphical Interpretation

As absolute temperature T increases, 1/T decreases, and the reaction rate constant k increases (ln k rises). Conversely, moving along the positive x-axis (increasing 1/T, meaning cooling), ln k falls linearly. The graph must therefore be a straight line sloping downward from left to right, exactly as illustrated in Plot (2).

d(ln⁡k)d(1/T)=−EaR=constant<0\frac{d(\ln k)}{d(1/T)} = -\frac{E_a}{R} = \text{constant} < 0
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 (1)
✗ Incorrect
Verdict & Scientific Reason:

Violates Arrhenius equation: positive slope implies reaction slows down upon heating.

⚠️
Student Fallacy (Why candidates pick this trap): Assuming rate constant is directly proportional to 1/T.
2 (2)
✓ 100% Correct
Verdict & Scientific Reason:

Matches Arrhenius slope m = -Ea/R < 0 and intercept c = ln A.

💡
Why this is airtight: None.
3 (3)
✗ Incorrect
Verdict & Scientific Reason:

Slope must be negative.

⚠️
Student Fallacy (Why candidates pick this trap): Flipping sign of Ea/R.
4 (4)
✗ Incorrect
Verdict & Scientific Reason:

Incorrect positive slope.

⚠️
Student Fallacy (Why candidates pick this trap): Plotting ln k versus T instead of 1/T.
⚠️

NTA Trap Alert: Confusing 1/T with Temperature T

Rate constant k increases with T (positive correlation), but 1/T is inversely related to T. Therefore, ln k decreases as 1/T increases!

🛡️ How to avoid the -1 mark: Higher 1/T means colder temperature, so the reaction is slower and ln k must be smaller.
📖

Core NEET Syllabus Standard

Chemistry Core Physical Chemistry · Chemical Kinetics Standard Benchmark
Core Scientific Principle Tested:

"The plot of ln k versus 1/T gives a straight line with slope = -Ea / R and intercept = ln A."

Syllabus Focus: Arrhenius Equation: Graphical Representation and Activation Energy
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗
As 1/T climbs, temperature goes low: The Arrhenius line must slope down below!

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