NEET 2024 Chemistry Question 58 Solution
Question
The energy of an electron in the ground state (n = 1) for He⁺ ion is −x J, then that for an electron in n = 2 state for Be³⁺ ion in J is:
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The energy of an electron in the ground state (n = 1) for He⁺ ion is −x J, then that for an electron in n = 2 state for Be³⁺ ion in J is:
Energy E ∝ (Z / n)². For He+ (n=1): (2/1)² = 4 -> -x J. For Be3+ (n=2): (4/2)² = (2)² = 4 -> exactly -x J!
For any one-electron hydrogen-like ion of atomic number Z, the energy of the stationary electron state with principal quantum number n is given by:
For helium ion He+, Z = 2. In the ground state, n = 1:
For beryllium ion Be3+, Z = 4. For the n = 2 quantum level:
Substituting -4 RH = -x directly into the expression:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Multiplies by (Z/n)² again instead of recognizing identical ratios.
Uses n = 3 in the denominator instead of n = 2.
Exact mathematical equality: (4/2)² = (2/1)² = 4.
Unrelated scaling error.
Students frequently square the numerator Z² = 16 but forget to square the denominator (dividing by 2 instead of 4, obtaining 8 instead of 4).
"Energy of hydrogen-like species scales as Z²/n²: En = -RH · (Z/n)²"
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