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Q.155 Zoology ⭐ 360° Option Elimination Active
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NEET 2021 Zoology Question 155 Solution

Topic: Molecular Basis of Inheritance · Official NTA Booklet Code M1
NEET 2021 Zoology Question 155: Chargaff's Equivalence Rule for Double-Stranded DNA

Question

If Adenine makes 30% of the DNA molecule, what will be the percentage of Thymine, Guanine and Cytosine in it?

  1. (1)T: 20; G: 30; C: 20
  2. (2)T: 20; G: 20; C: 30
  3. (3)T: 30; G: 20; C: 20
  4. (4)T: 20; G: 25; C: 25
✓
Verified Against NTA Final Answer Key
Option (3) : T : 30 ; G : 20 ; C : 20
📚 Molecular Basis of Inheritance Easy
📋 Given Parameters & Problem Setup
DNA Type Double-stranded DNA molecule
Adenine content (%A) 30%
Target Parameters % Thymine (%T), % Guanine (%G), % Cytosine (%C)
⚡

The 30-Second Exam Hall Shortcut: ⚡ "Chargaff's Law: %A = %T, and %G = %C = (100 - 2A) / 2"

⏱️ Save ~30 seconds

In double-stranded DNA, Adenine pairs with Thymine (%T = %A = 30%). A + T = 60%, leaving 40% equally divided between Guanine and Cytosine (%G = %C = 20%). Hence: T: 30, G: 20, C: 20. Match Option (3) in 10 seconds!

1 Set %T = %A = 30% (base complementarity A = T).
2 Calculate %G + %C = 100% - (%A + %T) = 100% - 60% = 40%.
3 By base complementarity (G = C): %G = 20% and %C = 20%.
4 Match Option (3): T : 30 ; G : 20 ; C : 20.
🛡️
Why You Can 100% Trust This Shortcut: NCERT Biology · Molecular Basis of Inheritance (Erwin Chargaff's rule: for dsDNA, [A] = [T] and [G] = [C], [A+G] = [T+C]).
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Formulation of Chargaff's Base Equivalence Rules

Erwin Chargaff established that in double-stranded DNA (dsDNA): 1. The molar ratio of Adenine (A) to Thymine (T) is always 1: [A]=[T][A] = [T]. 2. The molar ratio of Guanine (G) to Cytosine (C) is always 1: [G]=[C][G] = [C]. 3. The total percentage of all four nitrogenous bases equals 100%:

%A+%T+%G+%C=100%\%A + \%T + \%G + \%C = 100\%
Step 2

Step-by-Step Stoichiometric Calculation

Given that Adenine makes up 30%30\% of the DNA: - Because Adenine strictly pairs with Thymine via two hydrogen bonds (A=TA = T): %T=%A=30%\%T = \%A = 30\% - The sum of A and T is: %A+%T=30%+30%=60%\%A + \%T = 30\% + 30\% = 60\% - Therefore, the remaining fraction of the molecule comprises Guanine and Cytosine: %G+%C=100%−60%=40%\%G + \%C = 100\% - 60\% = 40\% - Because Guanine pairs with Cytosine via three hydrogen bonds (G≡CG \equiv C): %G=%C=40%2=20%\%G = \%C = \frac{40\%}{2} = 20\%

%T=30%%G=20%%C=20%\begin{aligned} \%T &= 30\% \\[3pt] \%G &= 20\% \\[3pt] \%C &= 20\% \end{aligned}
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 1
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. Sets T = 20%, which violates the fundamental base pairing requirement A = T (A was given as 30%).

⚠️
Student Fallacy (Why candidates pick this trap): Aspirants accidentally assign the 30% figure to Guanine instead of Thymine.
2 2
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. Again fails A = T and G = C parity.

⚠️
Student Fallacy (Why candidates pick this trap): Confusing purine-to-pyrimidine pairing partners.
3 3
✓ 100% Correct
Verdict & Scientific Reason:

Correct. Obeys Chargaff's rule: %A = %T = 30% and %G = %C = 20%, summing to 100%.

💡
Why this is airtight: None. Perfect mathematical and biological execution.
4 4
✗ Incorrect
Verdict & Scientific Reason:

Incorrect. Sums to 30 + 20 + 25 + 25 = 100%, but violates %A = %T.

⚠️
Student Fallacy (Why candidates pick this trap): Creating an arbitrary distribution of bases that totals 100% while ignoring base-pairing specificity.
⚠️

NTA Trap Alert: Applying Chargaff's Rules to Single-Stranded Nucleic Acids

Chargaff's equivalence rules apply strictly to double-stranded DNA. In single-stranded DNA (e.g. bacteriophage ϕ×174\phi \times 174) or RNA, %A does not necessarily equal %T or %U.

🛡️ How to avoid the -1 mark: Confirm the molecule is dsDNA before setting %A = %T and %G = %C.
📖

Core NEET Syllabus Standard

NEET / NCERT Biology · Molecular Basis of Inheritance Standard Benchmark
Core Scientific Principle Tested:

"In dsDNA, purines equal pyrimidines: %A = %T and %G = %C."

Syllabus Focus: Chargaff's Rules of DNA Base Composition
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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