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Q.19 Physics ⭐ 360° Option Elimination Active
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NEET 2021 Physics Question 19 Solution

Topic: Current Electricity · Official NTA Booklet Code M1
NEET 2021 Physics Question 19: Potentiometer Principle: Ratio of EMFs and Balancing Lengths

Question

In a potentiometer circuit a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire, the balance point occurs?

✓
Verified Against NTA Final Answer Key
Option (1) : 60 cm
📚 Current Electricity Easy
📋 Given Parameters & Problem Setup
Initial Cell EMF (E_1) 1.5 V
Initial Balancing Length (l_1) 36 cm
Replacement Cell EMF (E_2) 2.5 V
⚡

The 30-Second Exam Hall Shortcut: ⚡ Potentiometer Ratio Rule: l2 = l1 × (E2 / E1)

⏱️ Save ~20 seconds

Potential gradient is constant along the wire, so balancing length is strictly proportional to EMF: l∝El \propto E. Therefore, l2=36×2.51.5=36×53=12×5=60 cml_2 = 36 \times \frac{2.5}{1.5} = 36 \times \frac{5}{3} = 12 \times 5 = 60\text{ cm}! Instant 10-second calculation matching Option (1)!

1 Principle of potentiometer: E∝l  ⟹  E1E2=l1l2E \propto l \implies \frac{E_1}{E_2} = \frac{l_1}{l_2}.
2 Express l2l_2: l2=l1(E2E1)l_2 = l_1 \left(\frac{E_2}{E_1}\right).
3 Substitute: l2=36 cm×(2.5 V1.5 V)=36×53l_2 = 36\text{ cm} \times \left(\frac{2.5\text{ V}}{1.5\text{ V}}\right) = 36 \times \frac{5}{3}.
4 l2=60 cml_2 = 60\text{ cm}.
5 Match Option (1).
🛡️
Why You Can 100% Trust This Shortcut: Canonical potentiometer null deflection voltage-length proportionality.
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Formulating the Principle of a Potentiometer

For a uniform potentiometer wire carrying a steady current, the potential drop per unit length (potential gradient kk) is constant. At null deflection, the EMF of the test cell is balanced by the potential drop across balancing length ll:

E=k⋅l  ⟹  E∝lE = k \cdot l \implies E \propto l
Step 2

Setting Up the Proportionality Ratio

Comparing the two test cells balanced on the same potentiometer wire:

E1E2=l1l2  ⟹  l2=l1(E2E1)\frac{E_1}{E_2} = \frac{l_1}{l_2} \implies l_2 = l_1 \left(\frac{E_2}{E_1}\right)
Step 3

Substituting Given Numerical Values

Substitute l1=36 cml_1 = 36\text{ cm}, E1=1.5 VE_1 = 1.5\text{ V}, and E2=2.5 VE_2 = 2.5\text{ V}:

l2=36 cm×2.51.5=36×53=60 cml_2 = 36\text{ cm} \times \frac{2.5}{1.5} = 36 \times \frac{5}{3} = 60\text{ cm}
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 1
✓ 100% Correct
Verdict & Scientific Reason:

Exact balancing length for the 2.5 V cell: 36×(5/3)=60 cm36 \times (5/3) = 60\text{ cm}.

💡
Why this is airtight: None; textbook potentiometer derivation.
2 2
✗ Incorrect
Verdict & Scientific Reason:

Result of inverting the EMF ratio: 36×(1.5/2.5)=21.6 cm36 \times (1.5 / 2.5) = 21.6\text{ cm} (a higher EMF must produce a LARGER balancing length).

⚠️
Student Fallacy (Why candidates pick this trap): Inverting the ratio E1/E2E_1 / E_2.
3 3
✗ Incorrect
Verdict & Scientific Reason:

Arithmetic approximation error.

⚠️
Student Fallacy (Why candidates pick this trap): Rough estimation without exact calculation.
4 4
✗ Incorrect
Verdict & Scientific Reason:

Calculation error.

⚠️
Student Fallacy (Why candidates pick this trap): Rounding error.
⚠️

NTA Trap Alert: Inverted Ratio Trap

Students who accidentally multiply by E1/E2E_1 / E_2 obtain 21.6 cm21.6\text{ cm}, which NTA intentionally provided as Option (2). Since 2.5 V>1.5 V2.5\text{ V} > 1.5\text{ V}, the balancing length MUST be longer than 36 cm36\text{ cm}.

🛡️ How to avoid the -1 mark: Sanity check: Larger EMF requires a LONGER length to balance. l2>36 cml_2 > 36\text{ cm} immediately eliminates Option (2).
📖

Core NEET Syllabus Standard

NCERT Physics · Current Electricity Standard Benchmark
Core Scientific Principle Tested:

"In a potentiometer circuit, balancing length is directly proportional to the cell EMF: E1/E2=l1/l2E_1 / E_2 = l_1 / l_2."

Syllabus Focus: Potentiometer (Comparison of EMF of Two Cells)
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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