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Q.95 Chemistry ⭐ 360° Option Elimination Active
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NEET 2020 Chemistry Question 95 Solution

Topic: Aldehydes, Ketones and Carboxylic Acids · Official NTA Booklet Code E1
NEET 2020 Chemistry Question 95: Side-Chain Chlorination of Toluene Followed by Hydrolysis: Benzal Chloride Intermediate

Question

Identify compound X in the following sequence of reactions:

✓
Verified Against NTA Final Answer Key
Option (3) : C6H5-CHCl2 (Benzal chloride)
📚 Aldehydes, Ketones and Carboxylic Acids Easy
📋 Given Parameters & Problem Setup
Starting Material Toluene (C6H5-CH3)
Step 1 Reagents Cl2 / hν (Free radical side-chain chlorination)
Step 2 Reagents H2O at 373 K (Aqueous hydrolysis)
Final Product Benzaldehyde (C6H5-CHO)
Question Objective Identify compound X in the reaction sequence
⚡

The 30-Second Exam Hall Shortcut: ⚡ "Toluene + Cl2/hν -> C6H5-CHCl2 (Benzal Chloride) -> H2O/373K -> Benzaldehyde!"

⏱️ 20 seconds

Commercial preparation of Benzaldehyde: Side chain chlorination of toluene gives Benzal chloride (C6H5−CHCl2C_6H_5-CHCl_2). Hydrolysis of benzal chloride gives an unstable gem-diol (C6H5−CH(OH)2C_6H_5-CH(OH)_2), which spontaneously loses water to yield Benzaldehyde (C6H5−CHOC_6H_5-CHO). Thus, intermediate X is Benzal chloride! Mark Option (3) in 5 seconds.

1 Toluene + Cl2 / hν -> C6H5-CH2Cl (Benzyl chloride) with 1 eq Cl2.
2 Controlled chlorination with 2 eq Cl2 -> C6H5-CHCl2 (Benzal chloride) = Intermediate X.
3 Hydrolysis: C6H5-CHCl2 + 2 H2O -> [C6H5-CH(OH)2] -> C6H5-CHO + H2O.
4 Thus, X is Benzal chloride (C6H5-CHCl2).
5 Select Option (3).
🛡️
Why You Can 100% Trust This Shortcut: NCERT Chemistry · Aldehydes, Ketones and Carboxylic Acids (Preparation of Aldehydes: By Side Chain Chlorination Followed by Hydrolysis)
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Side Chain Chlorination of Toluene

Under photochemical conditions (light/heat), toluene undergoes free radical substitution at the benzylic methyl group rather than electrophilic ring chlorination: C6H5-CH3+2Cl2→hνC6H5-CHCl2+2HCl\text{C}_6\text{H}_5\text{-CH}_3 + 2\text{Cl}_2 \xrightarrow{h\nu} \text{C}_6\text{H}_5\text{-CHCl}_2 + 2\text{HCl} The compound formed is benzal chloride (benzylidene chloride, XX).

Step 2

Hydrolysis of Benzal Chloride

Nucleophilic substitution of the two geminal chlorine atoms by water at 373 K yields an unstable gem-diol intermediate: C6H5-CHCl2+2H2O→373 K[C6H5-CH(OH)2]+2HCl\text{C}_6\text{H}_5\text{-CHCl}_2 + 2\text{H}_2\text{O} \xrightarrow{373\text{ K}} [\text{C}_6\text{H}_5\text{-CH(OH)}_2] + 2\text{HCl}

Step 3

Spontaneous Dehydration to Benzaldehyde

Geminal diols attached to the same carbon are thermodynamically unstable and spontaneously undergo elimination of a water molecule: [C6H5-CH(OH)2]→−H2OC6H5-CHO (Benzaldehyde)[\text{C}_6\text{H}_5\text{-CH(OH)}_2] \xrightarrow{-\text{H}_2\text{O}} \text{C}_6\text{H}_5\text{-CHO (Benzaldehyde)}

Step 4

Identify Candidate Structure

Option (1) is Benzotrichloride (C6H5−CCl3C_6H_5-CCl_3, which would give Benzoic acid upon hydrolysis); Option (2) is Benzyl chloride (C6H5−CH2ClC_6H_5-CH_2Cl, which yields Benzyl alcohol); Option (3) is Benzal chloride (C6H5−CHCl2C_6H_5-CHCl_2). Hence, X is Option (3).

⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 A
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; hydrolysis of benzotrichloride gives benzoic acid (C6H5−COOHC_6H_5-COOH), not benzaldehyde.

⚠️
Student Fallacy (Why candidates pick this trap): Assuming exhaustive chlorination occurs.
2 B
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; hydrolysis of benzyl chloride gives benzyl alcohol (C6H5−CH2OHC_6H_5-CH_2OH), not benzaldehyde.

⚠️
Student Fallacy (Why candidates pick this trap): Stopping at mono-chlorination.
3 C
✓ 100% Correct
Verdict & Scientific Reason:

Factually exact; dichlorination at the benzylic carbon yields benzal chloride, which hydrolyzes directly to benzaldehyde.

💡
Why this is airtight: None; standard industrial synthesis of benzaldehyde described in NCERT.
4 D
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; ring chlorination occurs in presence of Lewis acids (FeCl3FeCl_3) in the dark, not under hνh\nu light irradiation.

⚠️
Student Fallacy (Why candidates pick this trap): Confusing free-radical side-chain chlorination with electrophilic aromatic substitution.
⚠️

NTA Trap Alert: Monochlorination vs Dichlorination vs Trichlorination

- Mono: C6H5CH2ClC_6H_5CH_2Cl -> Hydrolysis gives Benzyl ALCOHOL. - Di: C6H5CHCl2C_6H_5CHCl_2 -> Hydrolysis gives BENZALDEHYDE. - Tri: C6H5CCl3C_6H_5CCl_3 -> Hydrolysis gives BENZOIC ACID.

🛡️ How to avoid the -1 mark: Benzaldehyde requires TWO chlorines on the benzylic carbon: Benzal chloride (C6H5−CHCl2C_6H_5-CHCl_2)!
📖

Core NEET Syllabus Standard

Chemistry · Aldehydes, Ketones and Carboxylic Acids Standard Benchmark
Core Scientific Principle Tested:

""

Syllabus Focus: Side-Chain Chlorination of Toluene Followed by Hydrolysis: Benzal Chloride Intermediate
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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