NEET 2025 Chemistry Question 86 Solution
Question
Total number of possible isomers (both structural as well as stereoisomers) of cyclic ethers of molecular formula CHO is:
- (1)6
- (2)8
- (3)10
- (4)11
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Total number of possible isomers (both structural as well as stereoisomers) of cyclic ethers of molecular formula CHO is:
DBE = 1 (accounted for by the ring). 5-membered ring = THF (1). 4-membered ring = 2-methyloxetane (chiral C2 ⟹ 2) + 3-methyloxetane (1) = 3. 3-membered ring = 2-ethyloxirane (chiral C2 ⟹ 2) + 2,2-dimethyloxirane (1) + 2,3-dimethyloxirane (cis-meso + trans-d/l ⟹ 3) = 6! Total = 1 + 3 + 6 = 10!
Calculate the double bond equivalent (DBE) for C₄H₈O:
Systematically count structural and stereoisomers for oxolanes and oxetanes:
Examine substituted oxiranes (epoxides):
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Incorrect. Corresponds to counting structural isomers only without stereoisomers.
Incorrect. Omitting enantiomers of either oxetane or oxirane.
100% correct. Rigorous stereochemical enumeration yields exactly 10 isomers.
Incorrect. Overcounting meso form as two separate enantiomers.
There are exactly 6 STRUCTURAL cyclic ethers (THF, 2-methyloxetane, 3-methyloxetane, 2-ethyloxirane, 2,2-dimethyloxirane, 2,3-dimethyloxirane). When stereoisomerism is included, 2-methyloxetane adds +1, 2-ethyloxirane adds +1, and trans-2,3-dimethyloxirane adds +2 (with cis as meso), giving 6 + 4 = 10!
"Total isomers include all constitutional isomers, enantiomeric pairs, and meso diastereomers."
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