NEET 2024 Physics Question 34 Solution
Question
A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A. The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as 4π×10⁻⁷ SI units):
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A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A. The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as 4π×10⁻⁷ SI units):
B = μ₀NI / 2R -> [4 × (22/7) × 10⁻⁷ × 100 × 7] / (2 × 0.1) -> 7 cancels with 7 -> 88 × 10⁻⁵ / 0.2 = 4.4 × 10⁻³ T = 4.4 mT!
The magnitude of the magnetic field B at the center of a flat circular coil consisting of N closely wound turns carrying steady current I is given by the Biot-Savart law:
Substitute N = 100, I = 7 A, R = 10 cm = 0.1 m, and μ₀ = 4π × 10⁻⁷ T m/A:
Using π = 22/7 enables exact cancellation with the current of 7 A:
Dividing 88 by 0.2 gives 440:
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Exact evaluation: B = 4.4 × 10⁻³ T = 4.4 mT.
Off by four orders of magnitude (44 T is an immense, laboratory-record magnetic field).
Off by a factor of 10.
Confuses millitesla (mT) with tesla (T).
Options (1) and (4) differ solely by the prefix "m". Students frequently calculate 4.4 and overlook whether the unit is T or mT.
"The magnetic field at the center of a circular coil of N turns is B = μ₀NI / (2R)."
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