MyCompetitiveExams Logo MyCompetitiveExams
MyCompetitiveExams Logo MyCompetitiveExams
Search 1,140+ Questions
Chapters, formulas, speed tricks
→
⚡ Brahmastra NEET 2027
720 MARKS

Dynamic 180-question full-length simulator mixed dynamically from all 6 years for 2027 & 2026 aspirants.

Launch Brahmastra 2027 Test →
Start Practice →
100% Free · No Login Required
Q.30 Physics ⭐ 360° Option Elimination Active
Vault ↗

NEET 2021 Physics Question 30 Solution

Topic: Nuclei · Official NTA Booklet Code M1
NEET 2021 Physics Question 30: Radioactive Decay Law: Fractional Activity After Fractional Half-Lives

Question

The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be:

✓
Verified Against NTA Final Answer Key
Option (2) : 1 / (2√2)
📚 Nuclei Easy
📋 Given Parameters & Problem Setup
Half-Life (T_{1/2}) 100 hours
Elapsed Time (t) 150 hours
⚡

The 30-Second Exam Hall Shortcut: ⚡ Half-Life Count: n = 150/100 = 1.5 = 3/2

⏱️ Save ~20 seconds

Number of half-lives n=150100=1.5n = \frac{150}{100} = 1.5. Remaining fraction of activity is (12)3/2=123/2=122\left(\frac{1}{2}\right)^{3/2} = \frac{1}{2^{3/2}} = \frac{1}{2\sqrt{2}}! Instant 5-second calculation matching Option (2)!

1 Compute number of half-lives: n=tT1/2=150 h100 h=1.5=32n = \frac{t}{T_{1/2}} = \frac{150\text{ h}}{100\text{ h}} = 1.5 = \frac{3}{2}.
2 Remaining activity fraction: AA0=(12)n=(12)3/2\frac{A}{A_0} = \left(\frac{1}{2}\right)^n = \left(\frac{1}{2}\right)^{3/2}.
3 Simplify: 23/2=21×21/2=222^{3/2} = 2^1 \times 2^{1/2} = 2\sqrt{2}.
4 Thus, AA0=122\frac{A}{A_0} = \frac{1}{2\sqrt{2}}.
5 Match Option (2).
🛡️
Why You Can 100% Trust This Shortcut: Canonical Rutherford-Soddy exponential decay law and fractional half-life algebra.
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Formulating the Radioactive Decay Law for Activity

The activity A(t)=−dNdt=λN(t)A(t) = -\frac{dN}{dt} = \lambda N(t) follows the same exponential decay law as the number of undecayed nuclei. In terms of half-life T1/2T_{1/2}:

A(t)=A0(12)t/T1/2A(t) = A_0 \left(\frac{1}{2}\right)^{t / T_{1/2}}
Step 2

Determining the Number of Elapsed Half-Lives

Given half-life T1/2=100 hoursT_{1/2} = 100\text{ hours} and elapsed time t=150 hourst = 150\text{ hours}:

n=tT1/2=150100=1.5=32n = \frac{t}{T_{1/2}} = \frac{150}{100} = 1.5 = \frac{3}{2}
Step 3

Evaluating the Remaining Fraction

Substitute n=3/2n = 3/2 into the decay equation:

AA0=(12)3/2=123/2=123=18=122\frac{A}{A_0} = \left(\frac{1}{2}\right)^{3/2} = \frac{1}{2^{3/2}} = \frac{1}{\sqrt{2^3}} = \frac{1}{\sqrt{8}} = \frac{1}{2\sqrt{2}}
⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 1
✗ Incorrect
Verdict & Scientific Reason:

This is the fraction remaining after exactly 1 half-life (t=100 hourst = 100\text{ hours}), not 150 hours.

⚠️
Student Fallacy (Why candidates pick this trap): Ignoring the extra 50 hours of decay.
2 2
✓ 100% Correct
Verdict & Scientific Reason:

Exact remaining fraction calculated from exponential decay law: (1/2)1.5=1/(22)(1/2)^{1.5} = 1/(2\sqrt{2}).

💡
Why this is airtight: None; textbook radioactive decay calculation.
3 3
✗ Incorrect
Verdict & Scientific Reason:

Result of linear decay assumption: 1−(150/100)×(1/2)1 - (150/100) \times (1/2), which violates exponential decay.

⚠️
Student Fallacy (Why candidates pick this trap): Assuming radioactivity decays linearly with time.
4 4
✗ Incorrect
Verdict & Scientific Reason:

Arbitrary algebraic combination.

⚠️
Student Fallacy (Why candidates pick this trap): Incorrect exponent manipulation.
⚠️

NTA Trap Alert: Linear Interpolation vs. Exponential Decay Trap

Students who treat decay linearly think: "At 100 hrs it's 1/2, so at 150 hrs it's half of that again or 2/3". Exponential decay requires multiplying by factors of 1/21/2, so for 1.5 half-lives it is (1/2)1×(1/2)0.5=12×12=122(1/2)^1 \times (1/2)^{0.5} = \frac{1}{2} \times \frac{1}{\sqrt{2}} = \frac{1}{2\sqrt{2}}.

🛡️ How to avoid the -1 mark: Fraction remaining after nn half-lives is ALWAYS (1/2)n(1/2)^n. For n=1.5n = 1.5, (1/2)1.5=122(1/2)^{1.5} = \frac{1}{2\sqrt{2}}.
📖

Core NEET Syllabus Standard

NCERT Physics · Nuclei Standard Benchmark
Core Scientific Principle Tested:

"Activity decays exponentially according to A=A0(1/2)t/T1/2A = A_0 (1/2)^{t/T_{1/2}}."

Syllabus Focus: Radioactive Decay Law (Half-Life)
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

Ready to attempt under real exam pressure?

Test your speed and accuracy in the authentic 200-minute timed NTA simulator.

Launch NEET 2021 CBT Test →

Spotted a mistake in this solution? Report an error ([email protected])

⚖️ Legal & Fair Dealing Notice: Sourced from publicly released NEET 2021 question papers and NEET answer keys for private study, research, and non-commercial educational practice under Fair Dealing (Section 52(1)(a) of the Indian Copyright Act, 1957). Not affiliated with or endorsed by NTA or NMC.

Solve 4 NEET Questions a Day — One per Subject

Cover all 1,140 official NEET questions in 285 days at your own pace. Progress is saved on your device. No login needed.