NEET 2020 Physics Question 176 Solution
Question
Taking into account of the significant figures, what is the value of 9.99 m − 0.0099 m?
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Taking into account of the significant figures, what is the value of 9.99 m − 0.0099 m?
In addition and subtraction, the final result must retain as many decimal places as there are in the number with the least decimal places. In 9.99 m, there are 2 decimal places. In 0.0099 m, there are 4 decimal places. The subtraction 9.99 - 0.0099 = 9.9801 m must be rounded off to 2 decimal places, yielding 9.98 m. Mark Option (2) in 3 seconds!
For addition and subtraction of experimental measurements: 'The final result should retain as many decimal places as there are in the number with the least decimal places.'
- In , there are 2 digits after the decimal point. - In , there are 4 digits after the decimal point. The result must therefore be restricted to 2 decimal places.
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Looking at the third decimal digit in : it is (), so the preceding digit () remains unaltered. Rounded result = . Matches Option 2.
Diagnose every choice: Know exactly why the right option works and why distractors fail.
Incorrect; retains all mathematical digits without applying experimental significant figure rules.
Accurate value; rounded to 2 decimal places to match the least precise measurement (9.99 m).
Incorrect; has 3 decimal places instead of 2.
Incorrect; reduced to 1 decimal place unnecessarily.
Addition/subtraction is governed by the LEAST NUMBER OF DECIMAL PLACES, not least total significant figures. (Multiplication/division uses total significant figures).
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