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Q.105 Chemistry ⭐ 360° Option Elimination Active
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NEET 2020 Chemistry Question 105 Solution

Topic: Solutions · Official NTA Booklet Code E1
NEET 2020 Chemistry Question 105: Depression in Freezing Point Calculation: ΔTf = Kf × m

Question

The freezing point depression constant (Kf) of benzene is 5.12 K kg mol⁻¹. The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is (rounded off upto two decimal places):

✓
Verified Against NTA Final Answer Key
Option (3) : 0.40 K
📚 Solutions Easy
📋 Given Parameters & Problem Setup
Molal Depression Constant of Benzene (Kf) 5.12 K kg mol^-1
Molality of Solution (m) 0.078 m = 0.078 mol kg^-1
Solute Nature Non-electrolyte (van 't Hoff factor i = 1)
⚡

The 30-Second Exam Hall Shortcut: ⚡ "ΔTf = Kf × m = 5.12 × 0.078 ≈ 0.399 K ≈ 0.40 K!"

⏱️ 20 seconds

For a non-electrolyte (i=1i = 1), the depression in freezing point is given directly by ΔTf=Kf×m\Delta T_f = K_f \times m. Multiplying: 5.12×0.078=0.39936 K5.12 \times 0.078 = 0.39936\text{ K}. Rounded to two decimal places, this is 0.40 K0.40\text{ K}. Mark Option (3) in 10 seconds!

1 Formula: ΔTf = i × Kf × m.
2 For non-electrolyte solute: i = 1.
3 Compute product: ΔTf = 5.12 × 0.078.
4 Quick estimation: 5 × 0.08 = 0.40 K.
5 Exact: 5.12 × 0.078 = 0.39936 K ≈ 0.40 K.
6 Select Option (3).
🛡️
Why You Can 100% Trust This Shortcut: NCERT Chemistry · Solutions (Colligative Properties: Depression of Freezing Point)
📐

Step-by-Step Rigorous Workflow & Mathematical Proof

Step 1

Formula for Freezing Point Depression

Depression in freezing point (ΔTf\Delta T_f) is a colligative property directly proportional to the molal concentration of the solute in the dilute solution: ΔTf=i⋅Kf⋅m\Delta T_f = i \cdot K_f \cdot m

Step 2

Identify Parameters and van 't Hoff Factor

Because the solute is explicitly specified as a non-electrolyte, it undergoes neither association nor dissociation in benzene, so i=1i = 1. - Cryoscopic constant (KfK_f) = 5.12 K kg mol−15.12\text{ K kg mol}^{-1} - Molality (mm) = 0.078 m=0.078 mol kg−10.078\text{ m} = 0.078\text{ mol kg}^{-1}.

Step 3

Perform Multiplication

ΔTf=5.12×0.078\Delta T_f = 5.12 \times 0.078 ΔTf=0.39936 K\Delta T_f = 0.39936\text{ K}

Step 4

Round Off to Two Decimal Places

Rounding 0.39936 K0.39936\text{ K} to two decimal places gives: ΔTf≈0.40 K\Delta T_f \approx 0.40\text{ K} This precisely matches Option (3).

⭐

360° Option Elimination Engine Key Feature

Diagnose every choice: Know exactly why the right option works and why distractors fail.

4-Option Deep Scan
1 A
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; roughly half the actual product.

⚠️
Student Fallacy (Why candidates pick this trap): Division by 2 error.
2 B
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; double the correct depression.

⚠️
Student Fallacy (Why candidates pick this trap): Erroneously assuming a binary electrolyte with i=2i = 2.
3 C
✓ 100% Correct
Verdict & Scientific Reason:

Factually and mathematically exact; 5.12×0.078=0.39936 K≈0.40 K5.12 \times 0.078 = 0.39936\text{ K} \approx 0.40\text{ K}.

💡
Why this is airtight: None; direct colligative calculation.
4 D
✗ Incorrect
Verdict & Scientific Reason:

Incorrect; significant arithmetic overestimation.

⚠️
Student Fallacy (Why candidates pick this trap): Multiplying by 0.12 instead of 0.078.
⚠️

NTA Trap Alert: Non-Electrolyte van 't Hoff Factor

The problem says "non-electrolyte solute", which means i=1i = 1. Do not double the answer!

🛡️ How to avoid the -1 mark: Non-electrolyte = i=1i = 1. Direct product: 5.12×0.078=0.40 K5.12 \times 0.078 = 0.40\text{ K}.
📖

Core NEET Syllabus Standard

Chemistry · Solutions Standard Benchmark
Core Scientific Principle Tested:

""

Syllabus Focus: Depression in Freezing Point Calculation: ΔTf = Kf × m
✓ Core NEET UG Syllabus Anchor Syllabus & Academic Standards ↗

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